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MAVERICK [17]
4 years ago
9

A manufacturer or seller of a product may identify its merchandise and bar others from using the same identification by getting

a
A. franchise.
B. trademark.
C. patent.
D. copyright.
Mathematics
1 answer:
alexdok [17]4 years ago
5 0
This question is referring to a trademark.
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There are 5 puppies in a room. One puppy is 15 weeks, another is 9 weeks, another is 4 weeks, and another is 10 weeks. If the av
ANTONII [103]

Answer:

7

Step-by-step explanation:

If u add all 5 puppies ages together including the 7 week old one it will equal 45 divide that by 5 and you get an average of 9 weeks.

6 0
3 years ago
Let production be given by P = bLαK1−α where b and α are positive and α < 1. If the cost of a unit of labor is m and the cost
Nana76 [90]

Answer:

The proof is completed below

Step-by-step explanation:

1) Definition of info given

We have the function that we want to maximize given by (1)

P(L,K)=bL^{\alpha}K^{1-\alpha}   (1)

And the constraint is given by mL+nK=p

2) Methodology to solve the problem

On this case in order to maximize the function on equation (1) we need to calculate the partial derivates respect to L and K, since we have two variables.

Then we can use the method of Lagrange multipliers and solve a system of equations. Since that is the appropiate method when we want to maximize a function with more than 1 variable.

The final step will be obtain the values K and L that maximizes the function

3) Calculate the partial derivates

Computing the derivates respect to L and K produce this:

\frac{dP}{dL}=b\alphaL^{\alpha-1}K^{1-\alpha}

\frac{dP}{dK}=b(1-\alpha)L^{\alpha}K^{-\alpha}

4) Apply the method of lagrange multipliers

Using this method we have this system of equations:

\frac{dP}{dL}=\lambda m

\frac{dP}{dK}=\lambda n

mL+nK=p

And replacing what we got for the partial derivates we got:

b\alphaL^{\alpha-1}K^{1-\alpha}=\lambda m   (2)

b(1-\alpha)L^{\alpha}K^{-\alpha}=\lambda n   (3)

mL+nK=p   (4)

Now we can cancel the Lagrange multiplier \lambda with equations (2) and (3), dividing these equations:

\frac{\lambda m}{\lambda n}=\frac{b\alphaL^{\alpha-1}K^{1-\alpha}}{b(1-\alpha)L^{\alpha}K^{-\alpha}}   (4)

And simplyfing equation (4) we got:

\frac{m}{n}=\frac{\alpha K}{(1-\alpha)L}   (5)

4) Solve for L and K

We can cross multiply equation (5) and we got

\alpha Kn=m(1-\alpha)L

And we can set up this last equation equal to 0

m(1-\alpha)L-\alpha Kn=0   (6)

Now we can set up the following system of equations:

mL+nK=p   (a)

m(1-\alpha)L-\alpha Kn=0   (b)

We can mutltiply the equation (a) by \alpha on both sides and add the result to equation (b) and we got:

Lm=\alpha p

And we can solve for L on this case:

L=\frac{\alpha p}{m}

And now in order to obtain K we can replace the result obtained for L into equations (a) or (b), replacing into equation (a)

m(\frac{\alpha P}{m})+nK=p

\alpha P +nK=P

nK=P(1-\alpha)

K=\frac{P(1-\alpha)}{n}

With this we have completed the proof.

5 0
3 years ago
What is the amplitude of y = -8sin(3x)?
Sonbull [250]

Answer:

for y=-8sin(3x)

Amplitude = 8

3 0
3 years ago
Read 2 more answers
If you have 54 blue marbles and 99 yellow marbles, what is the greatest number of identical marble bags that can be made without
shepuryov [24]
The answer should be D) 18 because both 54 and 99 can divide by 3 and when you divide 54 by 3, you get 18 and that's the most bags you can have while still having both colors. Hope I could help.

5 0
4 years ago
Read 2 more answers
The cruising speed of a boeing 747 is 250 m/s. at this rate what distance does it travel in one minute?
Tems11 [23]
250m/s = x m/min
250m/s = x min/ 60s
250•60 = 1500
The airplane will travel 1500m per minute
7 0
4 years ago
Read 2 more answers
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