PLEASE HELP i need it !!!!!
1 answer:
Answer:
Step-by-step explanation: Area of triangle is base x height divided by 2. So do 8 + 8 to get the base which is 16m. 16 x 8 = 128/2 = 64 m^2
Area of a 1/4 circle is PI Radius ^2 then divided by 4. So *8^2 = 201.06/4 = 50.265 m^2
So to get the area of the entire figure you need to find the perimeter of the figure. So you should use the perimeter formula for each shape and then add all your perimeters of each shape. 1/4 Circle perimeter formula is C=2πr/4 . Perimeter of a square is P = 4a. Perimeter of a triangle is P =
a + b + c . Circle solving 50.27/4 = 12.5675 m^2. Triangle solving 8 + 8 + 16 = 32 m ^2 . Square solving 4 x 8 = 32 m ^ 2 .
This was so confusing and I dont know if this helps or not but I tried my hardest!
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Answer:
a) see attached
b) see attached
Step-by-step explanation:
There is existence of outlier in the Ni data and there is none is Cr data.
########################################
# You can try this out in R programming
cr = c(34, 1, 511, 2, 574, 496, 322, 424, 269, 140, 244, 252, 76, 108, 24,
38, 18, 34, 30, 191)
Ni = c(23, 22, 55, 39, 283, 34, 159, 37, 61, 34, 163, 140, 32,
23, 54, 837, 64, 354, 376, 471)
par(mfrow=c(1,2))
hist(cr, col='green')
hist(Ni, col='brown')
par(mfrow=c(1,2))
boxplot(cr, main = 'Boxplot of Cr')
boxplot(Ni, main = 'Boxplot of Ni')
boxplot(cr, Ni)
