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2 years ago

I need help badly again....

Mathematics

2 answers:

Shkiper50 [21]2 years ago

5 0

Hello!

First of all we need to find the area of the circle (A= $\pi$ r²). Our radius is one. We square it which leaves us with $\pi$ . Therefore we subtract pi from the triangle, which is 4√3.

Therefore, our answer is C) 4√3- $\pi$ square units.

I hope this helps!

taurus [48]2 years ago

4 0

The second answer is correct.

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Can you please help me solve this and show the solution 4y⁴+6y?

Pepsi [2]

Answer:

4y^4 + 6y = 256y + 6 = 262y

Step-by-step explanation:

Remove the variables for a second and think of the problem as a normal expression; 4^4 + 6

Simplify the first term; 4^4 = 256

Now, add 6; 256 + 6 = 262

Add back in the variable; 262y

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2 years ago

Read 2 more answers

WILL GIVE BRAINLIST PLS HELP Find x. Round your answer to the nearest tenth.

Llana [10]

Answer:

9. x=13.5

10. x=11.5

Step-by-step explanation:

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3 years ago

A study reported that the average age of menarche of girls entering the first year class of a small American private college in

Verizon [17]

Answer:

Null hypothesis: $\mu = 11.89$

Alternative hypothesis: $\mu \neq 11.89$

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=12.98$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n=30 represent the sample size

Solution to the problem

For this case we want to test the following hypothesis:

Null hypothesis: $\mu = 11.89$

Alternative hypothesis: $\mu \neq 11.89$

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

4 0

3 years ago

4 3/5 - 4/5 = ? please explain it ixl

miskamm [114]

Answer:

$\frac{19}{3 } \: or \: 3 \frac{4}{5}$