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Levart [38]
3 years ago
10

How to figure this problem out

Mathematics
1 answer:
Mamont248 [21]3 years ago
5 0
The answer is b because the problem is starting that
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The length of a rectangle is 4 more than its width. The area of the rectangle is 21m2 . What is the measure of the width?
iris [78.8K]
Length(l)= 4+ w
Width(w)=w
Area(A)= 21m^2

so keep in mind Area= Length × width

A= l×w
21=(4+w)(w)
21= 4w+ 2w
21=6w
w=3.5

The width is 3.5m

so the answer is about 4m
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The entry fee for a charity event is $15 per pair of people. The fee can be
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660

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3 years ago
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find the value of x2 values that separate the middle 90% from the rest of the distribution for 8 degrees of freedom
Anettt [7]

Answer:

With alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

Step-by-step explanation:

The significance level ∝ = 1- 0.9 = 0.1

But we need the area of the middle so we divide this significance level with 2

so that we get exactly the middle area .

Dividing 0.1/2= 0.05

So we will have two values for chi square

One with  0.9 + 0.05 = 0.95 alpha and one with 0.05 alpha . This is because the chi square is right tailed.

So with alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

This can be shown with a graph.

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3 years ago
Which scenario can be modeled using the graph below
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Graph is not listed

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