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Nina [5.8K]
3 years ago
14

Solve for v. 4v = -7 + 3v

Mathematics
2 answers:
goblinko [34]3 years ago
5 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>.</em>

<em>Hope </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>for</em><em> </em><em>your</em><em> </em><em>test</em><em>.</em><em>.</em><em>.</em>

<em>(. ❛ ᴗ ❛.)</em>

ser-zykov [4K]3 years ago
5 0

4v=(-7)+3v.

4v=−7+3v

Step 1: Simplify both sides of the equation.

4v=3v−7

Step 2: Subtract 3v from both sides.

4v−3v=3v−7−3v

v=−7

I hope this helps!

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The isotope cobalt-60 has a nuclear mass of 59.933820 u
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To start this question, we should know what is the atomic number of cobalt. The atomic number (the number of protons) of Cobalt is Z =27.

Now, we know that a Cobalt 60 isotope means an isotope of Cobalt whose Atomic Mass is 60.

Thus, in a Cobalt 60 isotope, the number of neutrons in the nucleus are

60-Z=60-27=33

From the question we know that the given nuclear mass is 59.933820 u.

Now, the mass defect of Cobalt 60 can be easily calculated by adding the masses of the protons and the neutrons as per our calculations and subtracting the given nuclear mass from it.

Thus,

Mass Defect = (Number of Protons Mass of Proton given in the question) + (Number of Neutrons Mass of Neutron given in the question)-59.933820 u

\therefore 27\times 1.007825+33\times 1.008665-59.933820=0.5634 u

Thus, the required Mass Defect is 0.5634u.

In eV, the Mass Defect is 931.5MeV\times 0.5634=534.807 MeV

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