Whats the mean, media, maximum,minimum,mode and range of 1,2,1,3,4
1 answer:
First put the numbers in order least to greatest.
(1,1,2,3,4)
The mean is the average of the group of numbers.
Too find it you add all the numbers up and divide it by how many numbers there are.
In this case it would be 11 divided by 5 so the mean would be
Median is just another word for middle. After putting the numbers in order, the number in the center of the group is the median, in this case it would be 2.
The maximum would just be the largest number which is self explantory (4)
The minimum would be the lowest number (1)
I was taught to see mode as the word "most". All you do is see which number occurs the most. If all the numbers only occur once, your answer would be "No mode"
<span>It is that simple! The Range is the difference between the lowest and highest number. So all you have to do is subtract the maximum by the minimum. In this case it would be 4-1 = 3
</span>
(1,1,2,3,4)
The mean is the average of the group of numbers.
Too find it you add all the numbers up and divide it by how many numbers there are.
In this case it would be 11 divided by 5 so the mean would be
Median is just another word for middle. After putting the numbers in order, the number in the center of the group is the median, in this case it would be 2.
The maximum would just be the largest number which is self explantory (4)
The minimum would be the lowest number (1)
I was taught to see mode as the word "most". All you do is see which number occurs the most. If all the numbers only occur once, your answer would be "No mode"
<span>It is that simple! The Range is the difference between the lowest and highest number. So all you have to do is subtract the maximum by the minimum. In this case it would be 4-1 = 3
</span>
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So, we can find the next 6 terms as shown below:
Answer:
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Step-by-step explanation:
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A cube has a surface area of 294 sq. In.
Now, to find the sides.
Let the side be
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<em>Dividing both sides by 6 we get:</em>
<em>Using square root on both sides we get:</em>
Side = 7 In.
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Answer:
<h2>The distance from the pitcher's mound and to second base is 37.99 approximately.</h2>Step-by-step explanation:
The diamond is a square, which in this case has 50 feet long each side, and from home to pitcher is 38 feet. Notice that home is a vertex of the square and the pitcher's mound is the intersection of the diagonals, where they cut half.
We can find the distance from the pitcher to first base using Pythagorean's Theorem, where 50 feet is the hypothenuse.
Therefore, the distance from the pitcher to first base is 32.5 feet, approximately.
Now, we can use again Pythagorean's Theorem to find the distance from pitcher to second base, where the hypothenuse is 50 feet.
Therefore, the distance from the pitcher's mound and to second base is 37.99 approximately.
<em>(this results make sense, because the diagonals of a square intersect at half, that means all bases have the same distance from pitcher's mound, so the second way to find the distance asked in the question is just using theory)</em>