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kolbaska11 [484]
3 years ago
15

How do I figure this out?

Mathematics
1 answer:
balu736 [363]3 years ago
6 0

it is 1 2 twelve I can end without 20 word my friend so deal with it

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Please help I am really struggling:(
Nastasia [14]
The equation would be 4(-22)-5
7 0
3 years ago
Read 2 more answers
Use the grouping method to factor this polynomial completely 3x^3+12x^2+2x+8
krok68 [10]

Answer:

(x+4)(3x^2 + 2)

Step-by-step explanation:

3x^3+12x^2+2x+8

3x^2(x + 4) + 2(x + 4)

(x+4)(3x^2 + 2)

3 0
3 years ago
Omg help with my homework PLEASE ASAP. what donu graph and how do i suow my workkkkk whats the answer
Gnoma [55]

Answer:

you have to start with you b which in your problem is 5 so put a point at 5 on the y-axis on your graph. then with the M (the fraction numbers) you have to move either up or down depending if there is a negative number. so yours is 1/2 so then you would start at the 5 point and go up 1 and right 2 then you just keep repeating till you get a few points and can make a line then you just do the same thing for the other equation. start at 3 on the y-axis and then go up 3 and right 4 then just keep repeating till you get a few point and can create a line at the end the lines should cross each other like perpendicular lines

Step-by-step explanation:

hope this helps:)

7 0
2 years ago
Find the value of x
sveticcg [70]

Answer:

<h2>          x = 15</h2>

Step-by-step explanation:

RQ < PR < PQ

TV < UV < UT

ΔPQR~ΔUTV   ⇒     \dfrac{RQ}{TV}=\dfrac{PR}{UV}

\dfrac{8}{x-3}=\dfrac{14}{x+6}\\\\8(x+6)=14(x-3)\\\\8x+48=14x-42\\\\48+42=14x-8x\\\\90=6x\\\\x=90:6=15

6 0
2 years ago
Fleta has $100.00 in a savings account that earns 5% interest
Aleonysh [2.5K]
First year 100x0.05 = 5
Second year 100x0.05 = 5
Third year 100x0.05 = 5
Total interest 15$ for three year + the original amount mean 100
Total after three year
$115

Because the interest not compounded mean : where previously accumulated interest is not added to the principal amount of the current period, so there is no compounding.
8 0
3 years ago
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