Question

In this triangle, what is the value of x?

Answer 1

Answer: $x=56.5\ km$

Step-by-step explanation:

Given the right triangle in the image, you need to remember the following identity:

$cos\alpha=\frac{adjacent}{hypotenuse}$

Observe the triangle. You can identify that:

$\alpha=28\°\\adjacent=x\\hypotenuse=64$

Then, knowing these values, you can substitute them into  $cos\alpha=\frac{adjacent}{hypotenuse}$:

$cos(28\°)=\frac{x}{64}$

Finally, you have to solve for "x".

Therefore, the value of "x" rounded to the nearest tenth is:

$64*cos(28\°)=x\\x=56.5\ km$