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aleksandrvk [35]
3 years ago
14

In this triangle, what is the value of x?

Mathematics
1 answer:
nalin [4]3 years ago
8 0

Answer: x=56.5\ km

Step-by-step explanation:

Given the right triangle in the image, you need to remember the following identity:

cos\alpha=\frac{adjacent}{hypotenuse}

Observe the triangle. You can identify that:

\alpha=28\°\\adjacent=x\\hypotenuse=64

Then, knowing these values, you can substitute them into  cos\alpha=\frac{adjacent}{hypotenuse}:

cos(28\°)=\frac{x}{64}

Finally, you have to solve for "x".

Therefore, the value of "x" rounded to the nearest tenth is:

64*cos(28\°)=x\\x=56.5\ km

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