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3 years ago

What is the y intercept of a line that has a slope of -3 and passes through the point (2,7)

1 answer:

5 0

Y = mx + b
slope(m) = -3
(2,7)...x = 7 and y = 2
now we sub and fund b, the y int
2 = -3(7) + b
2 = -21 + b
2 + 21 = b
23 = b <== ur y int

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What is the slope of a line that is parallel to the line y=-1/5?

Hitman42 [59]

Answer:

slope = 0

Step-by-step explanation:

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3 years ago

Write a equation that represents the line.

Shkiper50 [21]

Answer:

y= 4/5x -18/5

Step-by-step explanation:

First step is to find the slope using the points

(-3,-6) and (2,-2)

m = (y2-y1)/(x2-x1)

= ( -2- -6)/(2 - -3)

= (-2+6)/(2+3)

= 4/5

The using the slope intercept form of a line

y = mx+b where m is the slope and b is the y intercept

y = 4/5 x + b

Substitute a point into the equation

-2 = 4/5(2)+b

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Subtract 8/5 from each side

-2 -8/5 =b

-10/5 -8/5 =b

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3 years ago

A pig farmer owns a 20-arce farm and started business with 16 pigs. After one year, he has 421 pigs. Assuming a constant growth

IRISSAK [1]

Answer:

The correct answer is 206550 pigs.

Step-by-step explanation:

First of all you need to calculate the constant growth rate, which is given by the formula $p=((\frac{f}{s} )^{\frac{1}{y} } -1)*100$ where f is the value at the end of the year, s is the start value of that year, and y is the number of years.

From the excercise facts, we know that for 1 year (y=1), the final value is 421 (f=421), and the start value is 16 (s=16). Replacing them in the formula we get : $((\frac{421}{16}) ^{\frac{1}{1} } -1)*100 = 2531.25$ So, the constant growth rate equals 2531.25.

Next, we have to multiply the starting amount of pigs times the constant growth rate times the amount of time that passed to get the final quantity of pigs. This would be $16*2531.25*5.1$ and this gives us a total amount of 206550 pigs.

Have a nice day.

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2 years ago