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3 years ago

15

Geraldine is picking a four-digit password by using the digits 0 through 9. She can use each digit only once. How many different

passwords are possible?

2 answers:

Archy [21]3 years ago

6 0

0-9 = 10 numbers

1st digit can be 1 0f 10

2nd digit can be 1 of 9

3rd digit can be 1 of 8

4th digit can be 1 of 7

10 * 9 *8*7 = 5040 different combinations

VARVARA [1.3K]3 years ago

5 0

Answer:10 * 9 *8*7 = 5040 different combinations

Step-by-step explanation:

0-9 = 10 numbers

1st digit can be 1 0f 10

2nd digit can be 1 of 9

3rd digit can be 1 of 8

4th digit can be 1 of 7

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Step-by-step explanation:

Consider steps below;

$Total Possible Outcomes - 8C5,\\\\8! / 5! ( 8 - 5 )!,\\1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 / ( 1 * 2 * 3 * 4 * 5 )( 1 * 2 * 3 ),\\\\6 * 7 * 8 / 6 = Combinations - 56,\\\\$

$Number Of Outcomes - 6C5,\\\\6! / 5! ( 6 - 5 )!,\\1 * 2 * 3 * 4 * 5 * 6 / ( 1 * 2 * 3 * 4 * 5 ) ( 1 ),\\720 / 120 * 1,\\\\Outcomes - 6$

$Conclusion ; Solution - 6 / 56 = ( About ) 0.1071\\Hope That Helps!$

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