The question is incomplete. Here is the complete question.
Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -
x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.
Answer: L = 1; W = 9/4; A = 2.25;
Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:
A = x.y
A = x(-
)
A = -
To maximize, we have to differentiate the equation:
= 
(-)
= -3x + 3
The critical point is:
= 0
-3x + 3 = 0
x = 1
Substituing:
y = -x + 3
y = -.1 + 3
y = 9/4
So, the measurements are x = L = 1 and y = W = 9/4
The maximum area is:
A = 1 . 9/4
A = 9/4
A = 2.25
54000
54 x (10^3) = 54000
Answer: 
Step-by-step explanation:
From the given figure it can be seen that
Total number on cube= n(S)=6
Intersection of A and B = n(A ∩ B)= 2
Therefore,
Also, The number of elements in A = 2
Therefore,
Similarly, The number of elements in B= 6
Therefore,
The formula to find the conditional probability is given by :-
Answer:
6(6x + 4y), 12(3x + 2y), 4(9x + 6y)
Step-by-step explanation:
The expressions are equivalent to 36x + 24 y
Hope this helps! :)
