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4 years ago

Which expression is equivalent to 3(1 + x) + 7? B) x + 10 9 3x + 7 D 3x + 10

Mathematics

1 answer:

vaieri [72.5K]4 years ago

5 0

Answer:

D) 3x+10

Step-by-step explanation:

3(1+x)+7=3+3x+7=3x+10

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Katyanochek1 [597]

First fold = .02
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4 years ago

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Mary and Julie both have a goal of raising $1000 for

leonid [27]

Answer:

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Step-by-step explanation:

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3 years ago

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if the farmers market sold 35% of it produce and has 280 peaches remaining, how many peaches did it originally have on hand.

jonny [76]

Divide the amount left by the percentage left:

they sold 35%, so there is 65% remaining.

280 / 0.65 = 430.769

Round to 431

Now check:

431 x 0.35 = 150.85

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431 - 151 = 280 left.

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7 0

4 years ago

What is [[3^3-7)·5)/10]+((1+3+6+9)-)]

yanalaym [24]

Answer:

$\left(\left(3^3-7\right)\frac{5}{10}\right)+\left(\left(1+3+6+9\right)-1\right)=28$

Step-by-step explanation:

As far as I am able to observe from the statement of your question, the expression is:

$\left[[\left(3^3-7\right)\cdot \frac{5}{10}\right]+\left(\left(1+3+6+9\right)-1\right)$

So, lets solve this expression, which anyways would clear your concept

Considering the expression

$\left[[\left(3^3-7\right)\cdot \frac{5}{10}\right]+\left(\left(1+3+6+9\right)-1\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\left(3^3-7\right)\frac{5}{10}+1+3+6+9-1$

Lets first solve $\left(3^3-7\right)\frac{5}{10}$

As $3^3=27$

$=\frac{5}{10}\left(27-7\right)$

$=\frac{1}{2}\left(27-7\right)$

$=20\cdot \frac{1}{2}$

$=10$

So,

$\left(3^3-7\right)\frac{5}{10}+1+3+6+9-1 = 10+1+3+6+9-1$

= $28$

Therefore,

$\left(\left(3^3-7\right)\frac{5}{10}\right)+\left(\left(1+3+6+9\right)-1\right)=28$

Keywords: Expression solving

Learn more about solving expression from brainly.com/question/4687406

#learnwithBrainly

7 0

3 years ago

If f(x) = -x + 4 and g(x) = x^2 - 5, then g(f(3)) = ?<br> A) -8 <br> B) -4 <br> C) -3 <br> D) 0

kenny6666 [7]

Answer:

B) -4

Step-by-step explanation:

To solve g(f(3)), we first have to solve f(3):

Since f(x) = -x +4 , f(3) = -3 + 4 = 1

Now we have to solve g(1) , since that is what f(3) left us;

Since g(x) = x^2 - 5 , g(1) = 1^2 - 5 = 1 - 5 = -4

4 0

4 years ago