Answer:
24=12 or false
Step-by-step explanation:
All of given options contain quadratic functions. One way to determine the extreme value is squaring the expression with variable x.
Option B contain the expression where you can see perfect square. Thus, equation
(choice B) reveals its extreme value without needing to be altered.
To determine the extreme value of this equation, you should substitute x=2 (x-value that makes expression in brackets equal to zero) into the function notation:
The extreme value of this equation has a minimum at the point (2,5).
Answer:
Step-by-step explanation:
1) Step 4: Marc has converted radical form to exponent form
Step 5: He has evaluated the value of the radical
3)
![x = \sqrt[3]{8}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B8%7D)
Here, 3 is index and 8 is radicand.
Prime factorize 8 and for every 3 numbers we can take one number outside the radical
Solution:
![x = \sqrt[3]{2*2*2}\\\\x = 2](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B2%2A2%2A2%7D%5C%5C%5C%5Cx%20%3D%202)
4) No,my equation does not have an extraneous solution.
My solution, satisfies the equation
Step-by-step explanation:
let's assume one month is 30 days you would multiply 10 by 30.
![10 \times 30 = 300](https://tex.z-dn.net/?f=10%20%5Ctimes%2030%20%3D%20300)
which would be 300 hours in 1 month
now if one month is 31 days you would simply multiply 10 by 31.
![10 \times 31 = 310](https://tex.z-dn.net/?f=10%20%5Ctimes%2031%20%3D%20310)
which would be 310 hours
Hi !
the answer is 5y+4
please let me know if im wrong (: