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exis [7]
2 years ago
7

Negative 5 (2 1/6) equals.

Mathematics
1 answer:
mr Goodwill [35]2 years ago
7 0

Answer: -65/6

Step-by-step explanation:

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What is the interquartile range of the following set of numbers? 114, 90, 83, 101, 97, 142, 117, 87, 72
Likurg_2 [28]
Hello!

First we have to find the median

We have to order the numbers from least to greatest

72, 83, 87, 90, 97, 101, 114, 117, 142

The median is 97

Next we have to find quartile 1

you look for the median for the numbers under 97

It is 83 and 87

You get the average

83 + 87 = 170

170 / 2 = 85

quartile 1 is 85

Next we find quartile 3

Look for the median for the numbers above 97

The numbers are 114 and 117

Get the average

114 + 117 = 231

231/2 = 115.5

Now you find the range between the quartiles

You do quartile 3 - quartile 1

115.5 - 85 = 30.5

The answer is 30.5

Hope this helps!
5 0
4 years ago
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Can someone help me in this math problem? It’s a picture of the problem if you can!
lakkis [162]
Good job you got this
7 0
3 years ago
Use the distributive property to rewrite the expression and solve.<br><br> 9*72 = 9*?+ 9*2 =
Anastasy [175]
A(b+c)=ab+ac
we have
9(72)=9*?+9*2
c=2
sub, but it must be equal to minus 2 from 72
7(70+2)=9*70+9*2

the question mark is 70
and the restult of the equation is 648

?=70

7 0
3 years ago
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Kristine bought a vase that cost $5.99 and roses that cost $1.25 each. The total cost was $20.99.
LuckyWell [14K]

Answer:

5.99 + 1.25r = 20.99

Step-by-step explanation:

6 0
4 years ago
G prove that limx→∞(x 2 + 1)/x2 = 1 using the definition of limit at ∞.
Maslowich
\displaystyle\lim_{x\to\infty}\frac{x^2+1}{x^2}=1

means to say there is some number M for which any choice of \varepsilon>0 such that

x>M\implies\left|\dfrac{x^2+1}{x^2}-1\right|

Working backwards, we have

\left|\dfrac{x^2+1}{x^2}-1\right|=\left|1+\dfrac1{x^2}-1\right|=\dfrac1{x^2}
\implies\sqrt{\dfrac1{x^2}}

So, whenever x>M=\dfrac1{\sqrt\varepsilon}, we can always guarantee that \left|\dfrac{x^2+1}{x^2}-1\right|.
7 0
3 years ago
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