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3 years ago

8

A deli charges the same price, $5.00, for all of its different sandwiches. If a company ordered n sandwiches for a luncheon, whi

ch equation could be used to find the total price, P, that the deli charged for the sandwiches?

1 answer:

azamat3 years ago

7 0

Thats not possible to figure out because it does not say how many people went

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PLEASE HELP ME!!!!!!!!! Two stores carry a similar stereo for the same original price of $573. One store offers a 16% discount a

baherus [9]

The second store price is cheaper beacuse 16% of 573 gives off $91.68 and when u do that u get $481.32 so 458.40 is cheaper.

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3 years ago

Find the value of x and the value of y.

Margarita [4]

Answer:

s

wd\\\Step-by-step explanation:

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3 years ago

(2.5×10^−10)(7×10^−6)

Nataly [62]

<span>(2.5×10^−10)(7×10^−6)
= (2.5 x 7) (</span>10^−10 x 10^−6)
= 17.5 x 10^-16
= 1.75 x 10^-15

answer
<span>B. 1.75×10^−15 </span>

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3 years ago

The scatterplot below represents the number of hot drinks sold on a given

USPshnik [31]

Answer:

A) y=-1/2x+55

Step-by-step explanation:

We can clearly see a negative trend/association between the number of hot drinks sold on a given day and the low temperature of that day. Therefore, the slope of the best line of fit must be negative, eliminating D and E. Also, notice that when the low temperature is 0°F, the number of hot drinks sold is about 55, which is a good indicator of our y-intercept or constant, eliminating choice C. Because the best line of fit is not so steep, the slope will be closer to 0 if it's a negative trend. This eliminates choice B, making the correct answer A.

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2 years ago

A website manager has noticed that during the evening hours, about 5 people per minute check out from their shopping cart and m

Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is made

c) 0.05% probability that seven people make a purchase in the next four minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that $\mu = 5$

a) What model might you suggest to model the number of purchases per minute? 

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per minute.

b) What is the probability that in any one minute at least one purchase is made? 

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want to find $P(X \geq 1)$

So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067$

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is made

c) What is the probability that seven people make a purchase in the next four minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

$\mu = 4*5 = 20$

We have to find P(X = 7).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005$

0.05% probability that seven people make a purchase in the next four minutes

8 0

3 years ago