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Lisa [10]
3 years ago
8

A deli charges the same price, $5.00, for all of its different sandwiches. If a company ordered n sandwiches for a luncheon, whi

ch equation could be used to find the total price, P, that the deli charged for the sandwiches?
Mathematics
1 answer:
azamat3 years ago
7 0
Thats not possible to figure out because it does not say how many people went
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28.)Find the value of x.320(3x-10°A.) x = 22.67B.) x = 34.67C.) x = 21.6D.) x = 24.25
katen-ka-za [31]

Since the big triangle is an isosceles one, we conclude that the angles of the left triangle are: 32, 90 and 3x-10. Sinche the sum of this angles have to be 180° we have:

(3x-10)+32+90=180

Solving for x, we have:

\begin{gathered} (3x-10)+32+90=180 \\ 3x-10+32+90=180 \\ 3x=180+10-90-32 \\ 3x=68 \\ x=\frac{68}{3} \\ x=22.67 \end{gathered}

Therefore, x=22.67 and the answer is A.

7 0
2 years ago
The pH level of a solution measures how acidic or basic the solution is. Values between 0 and 7 are considered acidic while valu
Furkat [3]

Answer:

  about 2.47

Step-by-step explanation:

Your calculator will tell you ...

  -\log{(3.4\times 10^{-3})}\approx 2.4685\approx\bf{2.47}

4 0
3 years ago
Help pls! I need help with g. and 2. I don’t know what to do pls help.
Elza [17]

Answer:

Read it and do your best

Step-by-step explanation:

8 0
3 years ago
How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antif
konstantin123 [22]

440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze

<em><u>Solution:</u></em>

Let "x" be the gallons of 80 % antifreeze added

Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze

Final mixture is x + 80

Therefore, we can frame a equation as:

"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze

Thus, we get,

x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

x \times \frac{80}{100} + 80 \times \frac{15}{100} = (x+80) \times \frac{70}{100}\\\\0.8x + 80 \times 0.15 = (x+80) \times 0.7\\\\0.8x+12 = 0.7x+56\\\\0.8x-0.7x=56-12\\\\0.1x = 44\\\\x = \frac{44}{0.1}\\\\x = 440

Thus 440 gallons of 80 % antifreeze solution must be mixed

4 0
3 years ago
Jahyib has 421 dollars. He has 152 dollars more than kelsyann. How much money do Jahyib and Kelsyann have altogether?
zaharov [31]
Both of them together have 690 because you subtract 152 from 421 so...

421-152=269

Then add 269 to 421

421+269=690
3 0
3 years ago
Read 2 more answers
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