Ask question

Ask question

All categories

3 years ago

14

{ y = 3x - 4 y = x + 2

1 answer:

Savatey [412]3 years ago

3 0

X=3 and y=5 that's all

You might be interested in

Identifying the equivalent expression

iragen [17]

Answer:

$\large\boxed{\sqrt{x+3}=(x+3)^\frac{1}{2}}$

Step-by-step explanation:

$\text{Use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\sqrt{x+3}=\sqrt[2]{x+3}=(x+3)^\frac{1}{2}$

6 0

3 years ago

Identify the vertical cross section of the cylinder.

Sati [7]

Answer:

Rectangle

Step-by-step explanation:

if you split the shape in half vertically you won't get a circle, oval, and triangle isn't even anywhere in that picture.

so using the process of elimination it would have to be the first option. Rectangle.

5 0

2 years ago

A large fish tank at an aquarium needs to be emptied so that it can be cleaned. When its

VikaD [51]

Answer:

The draining time when only the big drain is opened is 2.303 hours.

The draining time when only the small drain is opened is 5.303 hours.

Step-by-step explanation:

From Physics, we know that volume flow rate ( $\dot V$ ), measured in liters per hour, is directly proportional to draining time ( $t$ ), measured in hours. That is:

$\dot V \propto \frac{1}{t}$

$\dot V = \frac{k}{t}$ (Eq. 1)

Where $k$ is the proportionality constant, measured in liters.

From statement, we have the following three expressions:

(i) <em>Large and small drains are opened</em>

$\dot V_{s}+\dot V_{l} = \frac{k}{2}$ (Eq. 2)

$\frac{\dot V_{s}+\dot V_{l}}{k} = \frac{1}{2}$

(ii) <em>Only the small drain is opened</em>

$\dot V_{s} = \frac{k}{t_{l}+3}$ (Eq. 3)

$\frac{\dot V_{s}}{k} = \frac{1}{t_{l}+3}$

(iii) <em>Only the big drain is opened</em>

$\dot V_{l} = \frac{k}{t_{l}}$ (Eq. 4)

$\frac{\dot V_{l}}{k} = \frac{1}{t_{l}}$

By applying (Eqs. 3, 4) in (Eq. 2) and making some algebraic handling, we find that:

$\frac{1}{t_{l}+3}+\frac{1}{t_{l}} = \frac{1}{2}$

$\frac{t_{l}+t_{l}+3}{t_{l}\cdot (t_{l}+3)} = \frac{1}{2}$

$2\cdot t_{l}+3 = t_{l}^{2}+3\cdot t_{l}$

$t_{l}^{2}-t_{l}-3 = 0$ (Eq. 5)

Whose roots are determined by the Quadratic Formula:

$t_{l,1}\approx 2.303\,h$ and $t_{l,2} \approx -1.302\,h$

Only the first roots offers a solution that is physically reasonable. Hence, the draining time when only the big drain is opened is 2.303 hours. And the time needed for the small drain is calculated by the following formula:

$t_{s} = 2.303\,h+3\,h$

$t_{s} = 5.303\,h$

The draining time when only the small drain is opened is 5.303 hours.

7 0

3 years ago

ashly lives 3/4 miles from her school. She walked 1/2 of the way from her home draw a model and work. and you have to do 3/4 x 1

Nezavi [6.7K]

Answer:

3/8?

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

I'm having a very hard time with geometry and was hoping someone could help me, sorry i know this isn't exactly a question

natulia [17]

Answer:

What kind of geometry EX. 6th grade 7th grade 8th grade Eureka etc.

Step-by-step explanation:

6 0

3 years ago