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gogolik [260]
3 years ago
5

What fraction of the Hexagon is shaded?

Mathematics
2 answers:
Natasha2012 [34]3 years ago
7 0
Hope the answer makes sense. Ask if you're confused.

irga5000 [103]3 years ago
4 0
64.8%. 12 times 10 is 120. 3 times 4 is 12 so the total area is 108. 108 divided by 100 is 1.08 times 60 is 64.8%
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4(x-6)&lt;-2x+6 what is the solution to the inequality <br> _
Cloud [144]
Simplify both sides if needed. The left-hand side needs simplification.

4(x - 6) \leq -2x + 6
4x - 24 \leq  -2x + 6

All is left to do is add and subtract to get the x variable all alone.

4x - 24  \leq -2x + 6
6x - 24  \leq  6    <-- Add 2x to both sides
6x         \leq  30  <-- Add 24 to both sides 
x           \leq 5    <-- Divide both sides by 6

In order to be in the solution set, x has to be less than or equal to 5.

In interval notation: [5, -∞)
7 0
3 years ago
Secant jkl and jmn are drawn to circle o from an external point ,j. if jk=8,lk=4 and jm=6 what is the length of jn answer
Archy [21]
See the picture attached to better understand the problem

we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm

we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12

jn=jl*jk/jm-----> jn=12*8/6----> jn=16

the answer is
jn=16

6 0
3 years ago
The cost to rent a bike is $8 per hour plus a 24$ flat fee if your final bill was $48 how many hours did you rent a scooter for?
Luda [366]
The scooter was rented for 3 hours
8 0
3 years ago
Read 2 more answers
Write the ratio as a ratio of whole numbers in lowest terms<br><br> $1.00 to $0.80
diamong [38]
5/4
as 1.00/0.80 = 100/80
and then when you simplify it the answer would be 4/5.
6 0
3 years ago
Which value for k makes the equation 42 ÷ k = 14 true
Rudiy27

Answer:

k=3

Step-by-step explanation:

6 0
2 years ago
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