Answer:
what is the question.
Step-by-step explanation:
I need the question
The first ten letters of the alphabet can be arranged 3,628,8000 different ways.
By the segment addition postulate,
AC + CE = AE so AC = AE - CE
AC = (x+50) - (x+32)
AC = x+50-x-32
AC = 18
It's probably A because the fact that it is multiplied by 4 wouldn't change the number of zeros, and 10 to the 3rd power would be 1000 (if you include the X4 in this example it would be 4000).
