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posledela
3 years ago
7

The perimeter of an equilateral triangle is 12 feet. Find the area of the triangle.

Mathematics
2 answers:
Montano1993 [528]3 years ago
4 0
The answer is 4√3 sq. unit
max2010maxim [7]3 years ago
3 0

Answer:

Option 3rd is correct

4\sqrt{3} square feet

Step-by-step explanation:

Perimeter(P) and Area(A) of equilateral triangle is given by:

P = 3a

A=\frac{\sqrt{3}}{4}a^2             ....[1]

where, a is the side of the equilateral triangle.

As per the statement:

The perimeter of an equilateral triangle is 12 feet

By definition of perimeter:

P = 3a

12 = 3a

Divide both sides by 3 we have;

4 = a

or

a = 4 ft

Substitute in [1] we have;

A = \frac{\sqrt{3}}{4}(4)^2 =\frac{\sqrt{3}}{4} \cdot 16 =4\sqrt{3} ft^2

Therefore, the area of the equilateral triangle is,  4\sqrt{3} square feet

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Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0
eduard
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2787701

_______________


\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}


Square both sides:

\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}

\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}


Since \mathsf{sin\,\theta} is positive, you can discard the negative sign. So,

\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}


Substitute this value back into \mathsf{(i)} to find \mathsf{cos\,\theta:}

\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

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