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4 years ago

A number is no less than seven. n > 7 n < 7 n ≥ 7 n ≤ 7

Mathematics

2 answers:

Damm [24]4 years ago

8 0

N > 7 this is the answer

natka813 [3]4 years ago

6 0

The answer is the third one

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Balloon arrangements are being made for a party. There are 35 white balloons and 45 purple balloons. Each arrangement must be id

natulia [17]

Answer:

Step-by-step explanation:

Find the greatest common factor of 35 and 45.

35 = 5×7

45 = 3²×5

There can be 5 identical arrangements made (arrangements of 7 white balloons and 9 red balloons).

3 0

3 years ago

Which of the following equations are examples of inverse variation? xy=c, cy=x, y=c/x, x=y/c, 1/y=xc

Masja [62]

Answer: $y=\frac{c}{x}$

Step-by-step explanation:

1. By definition, an inverse variaton is a relationship between two variables:

- When of them increases, the other one decreases.

- When one of them decreases, the other one increases.

2. An inverse variation has the following form:

$y=\frac{k}{x}$ ( $y$ is inversely proportional to $x$ )

Where $k$ is a nonzero constant.

3. The option that has the form shown above is:

$y=\frac{c}{x}$

Where $c$ is the nonzero constant.

3 0

3 years ago

Read 2 more answers

Name the marked angle in 2 different ways

Zolol [24]

Answer:

∠DEB or ∠BED

Step-by-step explanation:

The letter of the angle always goes in the middle.

8 0

3 years ago

Can someone please explain Linear Inequalities to me?

Zarrin [17]

Ok so an equation like y<_x+2 is not completely equal. a linear inequality is like that but just graphed, so basically a graphed unequal equation (<_ means equal to or greater) i hope this helped!

6 0

3 years ago

Read 2 more answers

A ball is shot from a cannon into the air. The equation that's gives the height (h) of the ball of any time (t) is: h(t)= -16t^2

Gre4nikov [31]

Answer:

26.5 units

Step-by-step explanation:

The height of the ball at any time t is given by :

$h(t)= -16t^2 + 40t + 1.5$ ...(1)

We need to find the maximum height of the ball.

For maximum height, put $\dfrac{dh}{dt}=0$

i.e.

$\dfrac{d( -16t^2 + 40t + 1.5)}{dt}=0\\\\-32t+40=0\\\\t=\dfrac{40}{32}\\\\t=1.25\ s$

Put t = 1.25 in equation (1) to find the maximum height.

So,

$h(t)= -16(1.25)^2 + 40(1.25) + 1.5\\\\=26.5\ units$

So, the maximum height reached by the ball is 26.5 units.

4 0

3 years ago