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lutik1710 [3]
3 years ago
8

Classify the sequence (an) =(1,16,31,46,...) as arithmetic, geometric, or neither. If there is not enough information to classif

y the sequence, choose not enough information.

Mathematics
2 answers:
erastovalidia [21]3 years ago
8 0

Answer:

arithmetic


Step-by-step explanation:

It is  arithmetic because the terms go up by 15 . That is the common difference is 15.

gtnhenbr [62]3 years ago
4 0

Answer:

it is an arithmetic sequence

Step-by-step explanation:

general formula of arithmetic progression is

an=a1+(n-1)d

we are given

a1=1

a2=16

we can find d

d=a2-a1=16-1=15

d=a3-a2=31-16=15

d=a4-a3=46-31=15

as we can see that there is a common difference d =15 between successive terms  of the this sequence

hence it is a arithmetic sequence


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TiliK225 [7]

Answer:

x = 29

Step-by-step explanation:

Given that both triangles are congruent to each other, therefore, their corresponding angles are congruent as well. This means all three angles in one is the same as all three corresponding angles of the other.

Therefore:

m<CAB = m<CDE = 74°

m<ABC = 2x (given)

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Thus:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?
Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are (x_{1}, y_1) and (x_2, y_2) then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})

Thus for our question the endpoints are (x_E, y_E) and (x_F, y_F) and hence the midpoint will be:

(x_M, y_M)=(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})

Thus, Option C is the correct option.

6 0
4 years ago
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