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3 years ago

9

PLEASEEEE HELLLPP: A team mom ordered 100 pizzas for $1255. Cheese pizzas cost $11.50 each and pepperoni pizzas cost $13.00 each

. Identify and define your variables. Write a sistem of equations.

1 answer:

tatiyna3 years ago

5 0

11.5c + 13p = 1255 ,c + p = 100 ,p=pepperoni pizza ,c=cheese pizza

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2 years ago

Which of the following is a solution of x2 + 6x = −18? x = 3 − 3i x = −3 + 3i x = −6 + 3i x = 6 − 3i

Marina86 [1]

Step 1 ) Move all terms right side of the equation.

$\displaystyle\ x^{2} + 6x = -18$

$\displaystyle\ x^{2} + 6x + 18 = -18 + 18$

$\displaystyle\ x^{2} +6x + 18 = 0$

Step 2 ) Apply quadratic formula. (Note: There are 2 solutions)

$\displaystyle\ x^{2} +6x + 18 = 0$

$\displaystyle\ x = \frac{-b\sqrt{b^{2}-4ac}}{2a}, \displaystyle\ x = \frac{-b-\sqrt{b^{2}-4ac}}{2a}$

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Step 3 ) Simplify.

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$\displaystyle\ x = \frac{-6-6i}{2}$

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Since the options only provide one of the answer we found, the answer is...

$\displaystyle\ x = -3 - 3i$

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- <em>Marlon Nunez</em>

6 0

2 years ago

Read 2 more answers

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It’s a grouping of linear(straight line)equations that deal with the same variables. Hope that helped?

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Step-by-step explanation:

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First we can set up our equation

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Next we can solve for x by multiplying by x and dividing by $cos 28$

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3 years ago

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the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

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Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

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Hence, the average was 9 years old find the average age of both groups is 10 years old.

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