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3 years ago

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PLEASEEEE HELLLPP: A team mom ordered 100 pizzas for $1255. Cheese pizzas cost $11.50 each and pepperoni pizzas cost $13.00 each

. Identify and define your variables. Write a sistem of equations.

1 answer:

tatiyna3 years ago

5 0

11.5c + 13p = 1255 ,c + p = 100 ,p=pepperoni pizza ,c=cheese pizza

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Helpppppp :((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((((9999

Anni [7]

Answer is C and E.

All of the other ones don't follow order of operations properly.

4 0

3 years ago

Determine whether each pair of expressions is equivalent.show your work. 4p + 3c and (c +2p)(2)

shtirl [24]

Answer:

Not equivalent

Step-by-step explanation:

4p + 3c

(c + 2p)(2)

2c + 4p

No equal

3 0

3 years ago

Read 2 more answers

Find the LCM of 315,420,525 using prime factorisation method with slove it

Vedmedyk [2.9K]

$\boxed{\sf \:\begin{cases}\\\begin{gathered} {\underline{{ \sf {\blue{\Large\bf \underbrace{ {\rm {\purple{\begin{array}{r | l}\large\rm{\red{ 5}}&\underline{315,420,525}\\\large\rm{\red{ 3}}& \underline{63,84,105}\\\large\rm{\red{3}}&\underline{21,28,35}\\\large\rm{\red{ 7}}&\underline{7,28,35}\\\large\rm{\red{2}}&\underline{1,4,5}\\\large\rm{\red{2}}&\underline{1,2,5}\\\large\rm{\red{5}}&\underline{1,1,5}\\&1,1,1\end{array}}}}} }}}}}\end{gathered}\\\end{cases}}$

LCM = 5 × 3 × 3 × 7 × 2 × 2 × 5

LCM = 6300

<u>Hence, the LCM of 315 , 420 , 525 is 6300</u>

5 0

3 years ago

Read 2 more answers

You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll

Misha Larkins [42]

Answer:

a. $P (R3 | G1)=\frac{1}{5}$

b. $P (R6| G3)= \frac{1}{3}$

c. $P(G3|E)=\frac{2}{3}$

d. $P (E|G3)=\frac{2}{3}$

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? $P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}$

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? $P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}$

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? $P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}$

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? $P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}$

6 0

3 years ago

Determine whether the ffunction X/(x^2-1) is odd even or neither

djyliett [7]

equation is:

$f(x) = \frac{x}{ {x}^{2} - 1 }$

so if its even f(-x) should be equal to f(x)

that means

$f( - x) = \frac{ - x}{ {( - x)}^{2} - 1} \\ \\ f( - x) = - \frac{ x}{ {x}^{2} - 1}$

so f(x) is not equal to f(-x) so its not even

If its odd than f(-x) should be equal to -f(x)

$- f(x) = - ( \frac{ x}{ { x}^{2} - 1 } ) \\ - f(x) = - \frac{ x}{ {x}^{2} - 1 }$

so as we can see f(-x)= - f(x)

so the function is odd

Ans:function is odd and not even

3 0

3 years ago