According to my calculations, the LCM of the two denominators is 50. Therefore, since 50 goes into 50 a total of 1 times, you would multiply the top and bottom of the first fraction by 1. And since 1 goes into 50 a total of 50 times, you would multiply the top and bottom of the second fraction by 50. Now that the denominators are the same, you can simply compare the numerators to determine which fraction is greater. Since 21 is less than 2100, 21/50 is less than 2100/50. Therefore the 1st entry (21/50) is less than the 2nd entry (42).
Answer:
At time t hours,
D(t) = √(5200t²)
Step-by-step explanation:
Charlies car is travelling at 40 miles/h while andy's car is travelling at 60 miles/h.
Now, distance = speed x time
Thus;
At a time t, the distance, covered by Charlie's car will be;
D1 = 40t
Similarly, At a time t, the distance, covered by Andy's car will be;
D2 = 60t
Using Pythagoras theorem,
D² = (40t)² + (60t)²
D² = 1600t² + 3600t²
D² = 5200t²
D = √(5200t²)