Answer:
7r³ - 3r² + 20r
Step-by-step explanation:
(9r³ + 5r² + 11r) + (-2r³ + 9r - 8r²)
You can get rid of the parentheses since there is nothing to distribute.
9r³ + 5r² + 11r - 2r³ + 9r - 8r²
Combine like factors.
7r³ - 3r² + 20r
No because the exponent on 6^3 is 216 and if you use (4•6)^3 then you’ll have to multiply the quotations and then Square it to the third
Answer: -6+13=7
Step-by-step explanation:
Answer:
a) Unit: College Student
Variables of measurement: Procrastination and illness habits.
b) Unit: SUV cars
Variables: Manufacturing and car damage for two car manufactures.
Step-by-step explanation:
We are given the following in the question:
In a research, a unit is a single individual or object that is measured.
a) A study finds that college students who often procrastinate tend to be sick more often than students who do not procrastinate.
Since college students are asked about procrastination, then the unit in this study is college students.
Unit: College Student
Variables of measurement: Procrastination and illness habits.
b) A study finds that sport utility vehicles (SUVs) made by one car manufacturer tend to be more heavily damaged in a crash test than SUVs made by a second car manufacturer.
Since all SUVs cars are considered, the unit in this research is SUV cars
Unit: SUV cars
Variables: Manufacturing and car damage for two car manufactures.
Q1. The answers are (–1, 8), (0, 7), (3, 18)
<span>–3x + y ≥ 7
</span>Let's go through all choices:
<span>(–2, –3)
</span>(-3) * (-2) + (-3) ≥ 7
6 - 3 ≥ 7
3 ≥ 7 INCORRECT
(–1, 8)
(-3) * (-1) + 8 ≥ 7
3 + 8 ≥ 7
11 ≥ 7 CORRECT
(0, 7)
(-3) * 0 + 7 ≥ 7
0 + 7 ≥ 7
7 ≥ 7 CORRECT
(1, 9)
(-3) * 1 + 9 ≥ 7
-3 + 9 ≥ 7
6 ≥ 7 INCORRECT
(3, 18)
(-3) * 3 + 18 ≥ 7
-9 + 18 ≥ 7
9 ≥ 7 CORRECT
Q2. The answers are:
5x + 12y ≤ 80
x ≥ 4
<span>y ≥ 0
</span>
<span>x - small boxes
</span><span>y - large boxes
</span>He has x small boxes that weigh 5 lb each and y large boxes that weigh 12 lb each <span>on a shelf that holds up to 80 lb:
5x + 12y </span>≤ 80
Jude needs at least 4 small boxes on the shelf: x ≥ 4
Let's check if y can be 0:
5x + 12y ≤ 80
5x + 12 * 0 ≤ 80
5x + 0 ≤ 80
5x ≤ 80
x ≤ 80 / 5
x ≤ 16
x ≥ 4 can include x ≤ 16
So, y can be 0: y ≥ 0
