The vector AB is found by subtracting the coordinates of point B from the coordinates of point A => (8, 3, 4) - (5, 7, - 2)
(8, 3, 4) - (5, 7, - 2) = (3, - 4, 6)
=>
a) a 3 x 1 column =
| 3 |
| -4 |
| 6 |
b) xi + yj + zk
=> 3i - 4j + 6k
Use the cross product to find the orthogonal vector, solve the parametric equation to see at which (t) the point + orthogonal vector intersects the plane, the distance is (t) * norm of vector
Answer:
d is it
Step-by-step explanation:
321-207 is actually equals to 114 but I mean the equation is false
Answer:
You can plot the lines by putting the values of x and y.
For y=x-2, if we put x= 2, then we got y=0
So, the point for this equation will be (2,0). Similarly, you can get many points for the equations and join them to plot lines in the graph.