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frozen [14]
4 years ago
7

dawn bought a winter coat at 30% off the original price.the discount on the coat was 21$.what was the original price of the coat

?
Mathematics
1 answer:
matrenka [14]4 years ago
7 0
The answer would be $30
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just olya [345]

The power increases by 21% per hour. 21% written as a decimal is 0.21.

Because it increases you would multiply the starting value by 1.21 times the number of hours (t).

That needs to be less than or equal to 100,00

The equation would be:

C: 15,040(1.21)t ≤ 100,000

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3 years ago
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masha68 [24]

Answer:

4 lbs left after 5 days

Step-by-step explanation:

First, you need to step up an equation!

You know that Soomin has a total of 20 pounds and that she's using it, so you are going to use subtraction.

She uses 3 1/5 pounds per day so you write:

20 - 3 1/5x

and you know that she wants to know how much she has left after 5 days so you replace the x with 5:

20 - (3 1/5) * 5

Multiply first:

20 - 16

After Subtracting you get the answer:

4 lbs left

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3 years ago
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HELLLLPPPPPPPP PLEASEEEEEEEEE
tatyana61 [14]

Answer:

10.5

Step-by-step explanation:

KET\cong KIT...... (given)

\therefore KE \cong KI.... (csct)

\therefore m(KE) =m(KI)

\therefore 10x-34= 4x + 29

\therefore 10x-4x= 34 + 29

\therefore 6x= 63

\therefore x=\frac{63}{6}

\therefore x=10.5

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3 years ago
Pls Help<br> I will mark as brainliest!!!!<br> which integer represents a golf score of 4 over par?
levacccp [35]

Answer:

Pls Help

I will mark as brainliest!!!!

which integer represents a golf score of 4 over par?

Step-by-step explanation:

I will mark as brainliest!!!!

which integer represents a golf score of 4 over par?Pls Help

I will mark as brainliest!!!!

which integer represents a golf score of 4 over par?

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3 years ago
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The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


6 0
3 years ago
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