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serious [3.7K]
3 years ago
10

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Mathematics
1 answer:
forsale [732]3 years ago
7 0

Answer:

Therefore,

m\angle R = 69.4\°

Step-by-step explanation:

Given:

In Right Angle Triangle PQR at ∠Q = 90° such that

RQ = 3     ....Adjacent side of angle R

PQ = 8     ....Opposite side of angle R

To Find:

m∠R = ?

Solution:

In Right Angle Triangle PQR, Tan Identity,

\tan R= \dfrac{\textrm{side opposite to angle R}}{\textrm{side adjacent to angle R}}

Substituting the values we get

\tan R= \dfrac{PQ}{QR}=\dfrac{8}{3}=2.6666\\\\\angle R=\tan^{-1}(2.666)=69.439=69.4\°

Therefore,

m\angle R = 69.4\°

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The Eastons traveled 180 miles on a trip to Grandma's house. At the end of the trip the odometer read 8,246 miles. Write and sol
aleksandr82 [10.1K]

Answer:

8246=x+180

x=8066 miles

Step-by-step explanation:

Let the initial readings be x

The final reading is the sum of initial reading and distance covered hence

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4 0
3 years ago
What is the product?
fredd [130]

Answer:

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}   =  \frac{2}{k + 2}

Step-by-step explanation:

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}

To solve the above, we need to follow the steps below;

4k+2 can be factorize, so that;

4k +2 = 2 (2k + 1)

k² - 4  can also be be expanded, so that;

k² - 4 = (k-2)(k+2)

Lets replace  4k +2  by  2 (2k + 1)

and

k² - 4 by  (k-2)(k+2)   in the expression  given

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}

\frac{2(2k+ 1)}{(k-2)(k+2)}   ×  \frac{k-2}{2k+1}

(2k+1) at the numerator will cancel-out (2k+1) at the denominator, also (k-2) at the numerator will cancel-out (k-2) at the denominator,

So our expression becomes;  

\frac{2}{k + 2}

Therefore, \frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}   =  \frac{2}{k + 2}

3 0
4 years ago
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djverab [1.8K]

<em>Answer:</em>

<em>Answer:3.33 </em>

<em>Answer:3.33 Step-by-step explanation:</em>

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>3.33</em>

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5 0
3 years ago
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