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3 years ago

⚠️ANSWER NEEDED SUPER FAST ⚠️ BRAINLIEST TO RIGHT AND QUICK ANSWER

Mathematics

2 answers:

nadezda [96]3 years ago

7 0

Answer:

15%

Step-by-step explanation:

k0ka [10]3 years ago

7 0

15% hopefully this helps

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Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam

Dvinal [7]

Answer:

Advance = $25

Same Day = $40

Step-by-step explanation:

I attached my work, hopefully it is clear. Same day tickets cost $40 and Advance tickets cost $25.

7 0

3 years ago

Vanessa is building a storage chest in the shape of a rectangular prism. The chest will be 59 cm long, 47 cm deep, and 27 cm hig

Gala2k [10]

Answer:

11270 cm2

Step-by-step explanation:

A = 2(wl+hl+hw)

= 2(47•59+27•59+27•47)

= 11270

3 0

3 years ago

Hailey spent $12 to buy 2 fish. Her cousin spent double the amount on fish. Each fish cost the same amount. How many fish do Hai

Greeley [361]

Haley spent $ 12....her cousin spent double....so her cuz spent $ 24

haley spent $ 12 for 2 fish...12/2 = 6 bucks per fish
so if the cuz spent $ 24....24/6 = 4.....cuz got 4 fish

haley's 2 fish + cuz's 4 fish = 6 fish in total

3 0

3 years ago

Read 2 more answers

A random sample of 16 men have a mean height of 67.5 inches and a standard deviation of 2.22.2 inches. Construct a 99% confiden

saw5 [17]

Answer: $\approx1.49$

Step-by-step explanation:

We know that the confidence interval for population standard deviation is given by :-

$\sqrt{\dfrac{(n-1)s^2}{\chi^2_{\alpha/2}}}$

, where n= sample size

s = sample standard deviation.

$\chi^2_{\alpha/2}$ and $\chi^2_{1-\alpha/2}$ = Chi-square critical value for degree of freedom (n-1) and significance level ( $\alpha$ ).

Given : $\alpha=1-0.99=0.01$

n= 16

Critical ch-square values for degree of freedom 15 and $\alpha=0.01$ will be :

$\chi_{\alpha/2}=\chi_{0.005}=32.80132$

$\chi_{1-\alpha/2}=\chi_{0.995}=4.6009$

Then , the required 99% confidence interval for the population standard deviation will be :

$\sqrt{\dfrac{(15)(2.2)^2}{32.80132}}$

$\sqrt{2.21332556129}$

$1.48772496157$

$\approx1.49$

Hence, the a 99% confidence interval for the population standard deviation :

4 0

3 years ago

Please help, thank you

alexandr1967 [171]

Answer:

falseeeeeeeee for sure

Step-by-step explanation:

can i get brianlissssstttt

4 0

3 years ago