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3 years ago

What is the slope of the line that passes through the points (3,6) and (1, 2)? Write

Mathematics

2 answers:

Anestetic [448]3 years ago

7 0

The slope would be 2. to find slope use the formula attached.

Margarita [4]3 years ago

5 0

Using the formula to calculate slope y2- y1/ x2- x1 we can insert the given points to make the equation 6-2/ 3-1 after subtracting we get 4/ 2 which can also be written as 2.

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Solve for m. m + 7 > 5

anastassius [24]

Answer:Move all terms not containing

to the right side of the equation.

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Multiply both sides of the equation by

⋅

Simplify both sides of the equation.

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Step-by-step explanation:

pls give me BRAINLIESTT PLSSSSSSS

5 0

3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago

The above is a a a a a a a a a a a a a a a a a a a

Reptile [31]

X f πxf

-1 2 -2

3 1 3

-1 -2 2

0 -3 0

total =3

mean (π)=πxf ÷n

= 3÷4

= 0.75 these is not answer I thank so

3 0

3 years ago

Tim walks 2/3 mile to school each day.He walks the same distance home. how far does he walk to and from school during a regular

klio [65]

About 6.7 miles for a week

5 0

3 years ago

Read 2 more answers

Please help! I'm super confused.

stich3 [128]

Answer:

10y + 2

Step-by-step explanation:

The formula for the perimeter of a rectangle or square is [length + length + width + width = perimeter or 2(length) + 2(width) = perimeter]

Our length here is y + 2. Either formula you use, [(y+2) + (y+2) or 2(y+2)] you should get the answer 2y + 4.

Next our width. The width is 4y-1. Either formula you use, [(4y-1) + (4y-1) or 2(4y-1)] you should get 8y - 2.

Then, simply add (2y+4) and (8y-2) to get 10y + 2. So, the perimeter of the garden is 10y + 2.

I hope this helps!

5 0

3 years ago