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SIZIF [17.4K]
3 years ago
15

Who could help me with this please and thank you

Mathematics
1 answer:
kkurt [141]3 years ago
4 0

Answer:

Step-by-step explanation:

let the number be x

so according to the question ur equation is

4x=5<x^2

4x-5=x^2

4-5=x^2/x

-1=x

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A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i
garri49 [273]

Answer:

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :  

Null hypothesis:\mu \leq 5  

Alternative hypothesis:\mu > 5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0
3 years ago
The credit remaining on a phone card (in dollars) is a linear function of the total calling time made with the card (in minutes)
saw5 [17]

Answer: $19.6

Step-by-step explanation:

Linear function: f(x)=mx+c

, where  m= rate of change in f(x) with respect to x.

c = Initial value.

Let c = Initial value of card , m= Charge per minute

x= Number of minutes calling time.

Then, 25.06= 38m+c   (i)

21.03=69m+c (ii)

Eliminate (ii) from (i)

4.03=-31m\\\\\Rightarrow\ m=\dfrac{4.03}{-31}\\\\\Rightarrow\ m=-0.13

Put m in (i) , we get

25.06= 38(-0.13)+c\\\\\Rightarrow\ 25.06=-4.94+c\\\\\Rightarrow\ c=25.06+4.94\\\\\Rightarrow\ c=30

i.e. f(x)=-0.13x+30

if x=80 then

f(80)= -0.13(80)+30

=-10.4+30

=19.6

Hence, the remaining credit after 80 minutes of calls = $19.6

7 0
3 years ago
If a cone has a volume of 338 cm^3 and a radius of 6 cm, how tall is it?
Anna35 [415]

The formula for the volume of a cone is V = πr²h ÷3

You are solving for the height, h.

V = 338 cm³ and r = 6 cm

338 = π(6)²h÷3

338 = π36h÷3

338 = π12h

28.16 = πh

8.965 = h

The height of the cone is around 9 cm.

6 0
3 years ago
Can somebody please help me???
matrenka [14]

Answer: B

Step-by-step explanation:

Domain is x values

Range is y values

Domain you look from left to right. You can see it starts at -3, and it goes all the way to 2. NOT 4 BUT 2!! Since we are looking at the X.

Range.. WE ARE LOOKING AT THE LOWEST POINT!! LOWEST POINT FIRST!1 I cannot stress enough. The lowest y-value is -2, and it's maximum point is 4!

REMEMBER:

DOMAIN = X LEFT TO RIGHT

RANGE= Y LOWEST POINT TO HIGHEST

8 0
3 years ago
Read 2 more answers
16+28÷2-6 over 10-4x2
Levart [38]

Answer:

-11(over)10-4x^2

8 0
3 years ago
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