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3 years ago

8

Help!!!!!! Will give Brainlist answer!!!! 3 parts pls thank you so much

1 answer:

wariber [46]3 years ago

6 0

Part A
The small red arcs indicate that angles PQS and RQS are congruent.

13x - 1 = 2(6x + 4)

13x - 1 = 12x + 8

x = 9

m<PQR = 13x - 1 = 116

m<RQS = 6x + 4 = 6(9) + 4 = 58

m<PQS = 116 - 58 = 58

Part B

12^2 + (OH)^2 = 13^2

144 + (OH)^2 = 169

(OH)^2 = 25

OH = 5

r = OH = 5

Part C

WZ/ZY = WX/XY

24/12 = 30/XY

2 = 30/XY

2(XY) = 30

XY = 15

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Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

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$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

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$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

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$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

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