Answer:
Step-by-step explanation:
z + 4 = 75 z + 4 = 75 z + 4 = 75 z + 4 = 75 z + 4 = 75 z + 4 = 75 z + 4 = 75 z + 4 = 75 z + 4 = 75 z + 4 = 75 z + 4 = 75 z + 4 = 75
Answer:
mean: 220
median: 219
mode: 195
lower extreme: 157
upper extreme: 270
range: 113
lower quartile: 200.5
upper quartile: 241
interquartile range: 40.5
Step-by-step explanation:
(for the box and whisker plot look up examples and list the quartile ranges)
Area of rectangle it's the width multiply by the lenth.
A=W*L
A=38 1/4 m²
W=4 1/2 m²
So: 38 1/4 = 4 1/2 * L
Dividing both sides by 4 1/2: : 4 1/2 :4 1/2
Answer: T<span>he length of the garden is 8 1/2 meters</span>
4. You would need to set up equations. Two per problem. So 5x+2s=98. And 9x+2s=154. Then you would multiply one of them by a negative one to make the 2 student tickets cancel out. I would use the top one. So it turns to -5c-2s=-98. The -2c and 2c cancel out. You put the rest together to get 4X=56. And 56/4 is 14. So the senior tickets (X) are 14$. You would then replace X with fourteen one of the original equations. Again I'm going to use the first one. So 5(14)+2c=98. 5x14 is 70. Subtract 70 from both sides to get 2c=28. Divide both sides by 2 to get C=14. So the student tickets are 14$ and the seniors are also 14$.
5. Same thing on this one. Two equations. 8h+7i=84 and 3h+1i=25. Like going to multiply the second equation by -7 so the i's will cancel out to get -21h-7i=-175. So you will end up with -13h=-91. Divide both sides by -13 to get H=7. Replace H in one of the equations. I'll use second one. So 3(7)+1i=25. 3x7=21 so subtract 21 from both sides to get i=4. So the ivy is 4$ and the hostas are 7$.
Hope that helped a little bit!
Problem 9
r+h = 9
SA = 2*pi*r^2 + 2*pi*r*h = 54pi
2*pi*r^2 + 2*pi*r*h = 54pi
2pi*r(r + h) = 54pi
r(r+h) = 27
r(9) = 27
9r = 27
r = 27/9
r = 3
r+h = 9
h = 9-r
h = 9-3
h = 6
Answers: r = 3 and h = 6 are the radius and height respectively.
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Problem 10
d = diameter = 68 mm
r = radius = d/2 = 68/2 = 34 mm
SA = surface area of a sphere
SA = 4*pi*r^2
SA = 4*pi*34^2
SA = 4264pi
Answer: 4264pi square mm
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Problem 11
Plug V = 3000 into the sphere volume formula and isolate r.
V = (4/3)pi*r^3
3000 = (4/3)pi*r^3
(4/3)pi*r^3 = 3000
4pi*r^3 = 3*3000
4pi*r^3 = 9000
r^3 = 9000/(4pi)
r = cube root( 9000/(4pi) )
r = ( 9000/(4pi) )^(1/3)
r = 8.947002 approximately
Now we can determine the surface area of this sphere.
SA = 4pi*r^2
SA = 4*pi*( 8.947002 )^2
SA = 1005.923451
Answer: 1005.923451 square feet approximately
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Problem 12
We'll follow the same idea as problem 11, but in reverse.
SA = 4*pi*r^2
400pi = 4pi*r^2
r^2 = (400pi)/(4pi)
r^2 = 100
r = sqrt(100)
r = 10
Luckily we get a nice whole number for the radius r. Use it to find the volume.
V = (4/3)*pi*r^3
V = (4/3)*pi*10^3
V = (4000/3)pi
Answer: (4000/3)pi cubic inches exactly
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Problem 13
The diagram is missing. I don't have enough info to be able to answer.