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krok68 [10]
2 years ago
8

How many pairs of two digit natural numbers have a difference equal to 50

Mathematics
1 answer:
dangina [55]2 years ago
3 0

The number exists 99, then 99 - 49 = 50

Therefore, the pair of two-digit numbers exist between 99 and 49.

<h3>What is the difference?</h3>

In math, the word difference exists as the outcome of subtracting one number from another.

Let the first pair of two-digit numbers be xy and the second pair of numbers be yx.

we want a two-digit number, a two-digit number begins from 10 and ends with a two-digit number that exists 99.

Let the difference of 50 exists possible when we take the biggest two-digit number

Therefore, the number exists 99

99 - 49 = 50

Therefore, the pair of two-digit number exists 99 and 49.

To learn more about differences refer to:

brainly.com/question/14335054

#SPJ9

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How many grams of NH3 are required to produce 4.65 g of HF
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1.326 grams of NH3 are required to produce 4.65 g of HF.

Step-by-step explanation:

Balanced chemical reaction is written first to know the number of moles taking part in original reaction.

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Given:

mass of HF = 4.65

First the number of moles of HF in 4.65 grams is calculated by using the formula:

number of moles (n) = \frac{mass}{atomic mass of 1 mole}

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putting the values in the above equation number of moles can be found.

n = \frac{4.65}{20}

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From the equation it can be said that:

1 mole of NH3 reacts to form 3 moles of HF

so, x moles of NH3 would react to form 0.235 moles of HF

\frac{3}{1} = \frac{0.235}{x}

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x = \frac{0.235}{3}

x = 0.078 moles of NH3 is required.

The moles are converted to mass by applying the formula:

mass = atomic mass X number of moles (atomic mass of NH3 = 17 grams/mole)

        putting the values in the formula

mass = 17 X 0.078

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