Answer:
Marry = $17
Ravi = $11
Alan = $34
Step-by-step explanation:
Let us assume
Mary be X
Ravi be Y
Alan be Z
So, the equation in total is
X + Y + Z = 62
It is given that
X = Y + 6
Z = 2X
Now we put the Z value in the total equation, so it would be
X + Y + 2X = 62
3X + Y = 62 .................................... (1)
And can we write
X = Y + 6
X - Y = 6 ................................. (2)
Now substitution these two equations,
3X + Y = 62
X - Y = 6
2X = 68
X = $17
So, Z = 2 × 17 = $34
And, Y
$17 + Y + $34 = $62
So, Y = $11
2. because each x number times 2 plus one is equal to the y range
Answer:

Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by

where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:

reduce fraction:

By using calculator we acquire:

hence, the remaining sample after 420 days is 0.625 kg
Answer:
The diameter is 91.
Step-by-step explanation:
The formula for circumference is 2*pi*radius(you can use circumference = diameter*pi too). Plug 285.74 into it. Divide both sides by 3.14, and you get 2*radius(aka the diameter) = 91
Answer:
The proportion of the offspring from the cross PpRr × PpRr that are expected to have white flowers and wrinkled seeds is 1/16 or 6.25%.
Step-by-step explanation:
The uppercase letter represents the dominant allele, while the lowercase represents the recessive allele. The dominant allele determines the phenotype (observable trait) when it is present.
When you cross heterozygous individuals for each trait, each individual of the offspring has the probability of 1/6 of each combination of four alleles (two for each trait). Because the dominant allele determines the phenotype when it is present, the probability of dominant phenotypes is higher than recessive phenotypes.
Proportions of each phenotype in the offspring from the cross PpRr × PpRr are:
Purple flowers with round seeds: 9/16
Purple flowers with wrinkled seeds: 3/16
White flowers with round seeds: 3/16
White flowers with wrinkled seeds: 1/16
The proportion of individuals with white flowers and wrinkled seeds is the lowest because they are homozygous recessive for both traits.