The notation
h: x --> ax+b
is another way of saying h(x) = ax+b
The input is x, the output is h(x) = ax+b
The composite function notation h^2 is the same as (h o h)(x) or h(h(x)). I prefer h(h(x)) as it is the most descriptive of the three notation styles. The square notation is easily confused with actual squaring (when instead we want composite notation of a function with itself)
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h(x) = ax+b
h(x) = a( x )+b
h(h(x)) = a( h(x) )+b ... replace every x with h(x)
h(h(x)) = a( ax+b )+b .... replace the h(x) on the RHS with ax+b
h(h(x)) = a*ax + ab + b
h(h(x)) = a^2*x + (ab + b)
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Since h(h(x)) = 36x-35, this means we can equate the two expressions to find a and b
a^2*x + (ab+b) = 36x-35
we see that
a^2 = 36, so a = 6 (keep in mind a > 0)
since a = 6, we know that
ab+b = -35
6b+b = -35
7b = -35
b = -35/7
b = -5
9514 1404 393
Answer:
y-4 = -2(x+1)
Step-by-step explanation:
The point-slope equation of a line is ...
y -k = m(x -h) . . . . . line with slope m through point (h, k)
You have m = -2 and (h, k) = (-1, 4). Putting these numbers into the above form gives ...
y -4 = -2(x +1)
A]
3x^3y+15xy-9x^2y-45y
=3x^3y+3*5x*y-3*3x^2*y-3*15y
factoring 3y we get:
3y(x^3+5x-3x^2-15)
B]
Factoring the expression we get:
3x^3y+15xy-9x^2y-45y
=3xy(x^2+5)-9y(x^2+5)
=(3xy-9y)(x^2+5)
First simplify
6x-54=4x-20
add 20 to both sides
6x-34=4x
subtract 6x from both sides
-34=-2x
divide by -2 on both sides
17=x