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babymother [125]
3 years ago
15

Complete the equation to make a true statement. 12,000 lb = ____ T

Mathematics
2 answers:
Lilit [14]3 years ago
7 0
There are 2,000lbs in a ton, there for 12,000lbs= 6T.
galina1969 [7]3 years ago
6 0
6 tons I think. I think this because 2,000 pounds equals 1 US Ton. So if there is 12,000 pounds think what 12 divided by 2 is. It's 6. So that's the answer. 
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Artyom0805 [142]
Hey there,

Answer:

Rate = Distance / Time
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What is the force acting on a 16 kg object accelerating at 2.0 m/s2
alexira [117]

Answer:

32 n

Step-by-step explanation:

I had the same problem but I used a net force calculator the formula is F=MA so it would be 32=16/2.0 :)

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I need help x-x please
KengaRu [80]


60 - 45 = 15
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3 years ago
4x:3 = 6:5 calculate the value of x
My name is Ann [436]

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-2

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4x:3=6:5.

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4 0
2 years ago
Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
3 years ago
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