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3 years ago

How to solve 8x^3+1=0

1 answer:

6 0

8x^3 + 1 = 0
8x^3 = -1 <----------- Step 1: Subtract 1 from both sides.
x^3 = -1/8 <----------- Step 2: Divide both sides by 8.
x = ∛(-1/8) <----------- Step 3: Cube root both sides
x = -0.5 <----------- This is the final answer when you plug the last step into the calculator

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Graph the function f(x)=32x−4. Use the line tool and select two points to graph.

muminat

Answer:

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4 years ago

Read 2 more answers

Which transformation on the coordinate plane is a dilation?

Kaylis [27]

Answer:

It is the third one

Step-by-step explanation:

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3 years ago

PLEASE HELP ME!!!!!!!!!!!!!!!!!!

lilavasa [31]

Answer:

a) 4 - $vt - d = \frac{1}{2} at^{2}$

b) 1 - $2(vt - d) = at^{2}$

c) 6 - $\frac{2(vt - d)}{t^{2}} = a$

Step-by-step explanation:

It simply asks the steps to go from the original displacement formula to isolate a (the acceleration). It's just a matter of moving items around.

We start with:

$d = vt - \frac{1}{2} at^{2}$

We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):

$vt - d = \frac{1}{2} at^{2}$

Then we multiply each side by 2 to get rid of the 1/2, answer #1:

$2(vt - d) = at^{2}$

Finally, we divide each side by t^2 to isolate a (answer #6):

$\frac{2(vt - d)}{t^{2}} = a$

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3 years ago

Solve this quadratic equation.<br> x2 + 5x + 3 = 0

Xelga [282]

Answer:

Step-by-step explanation:

2x+5x+3=0

7x+3=0

-3 -3

=0 =-3

7x=-3

-3/7=-0.42857142857

x=-0.42857142857

I think it is right

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3 years ago