Answer:
As I understand it asks for (fog)(x)
We know f(x)= 2x + 2
And g(x) = x^2 + 1
It is going to be like we are putting g(x) inside the f(x).
So you are going to write g(x) wherever you see a x.
Step-by-step explanation:
f(x)= 2x + 2 <-- do you see the x there, so just wrote g(x) formula instead of x.
g(x) = x^2 + 1
So, it will look like this:
(fog)(x) = 2(x^2 + 1) + 2
You also can simplify this with multiplying by 2 in front ; 2x^2 + 2 +2 and you can add two 2s finally it will be, 2x^2 +4
Hope it was clear, let me knoq if you have any questions.
