Question

If f(x) = 3x + 2 and g(x) = x2 + 1, which expression is equivalent to (f circle g) (x)? (3x + 2)(x 2 + 1) 3x 2 + 1 + 2 (3x + 2)2 + 1 3(x 2 + 1) +

Answer 1

Answer:

As I understand it asks for (fog)(x)

We know f(x)= 2x + 2

And g(x) = x^2 + 1

It is going to be like we are putting g(x) inside the f(x).

So you are going to write g(x) wherever you see a x.

Step-by-step explanation:

f(x)= 2x + 2 <-- do you see the x there, so just wrote g(x) formula instead of x.

g(x) = x^2 + 1

So, it will look like this:

(fog)(x) = 2(x^2 + 1) + 2

You also can simplify this with multiplying by 2 in front ; 2x^2 + 2 +2 and you can add two 2s finally it will be, 2x^2 +4

Hope it was clear, let me knoq if you have any questions.

Answer 2

Answer:

(3x+2)^2+1

Step-by-step explanation:

(f°g)(x) =g(f(x)) =g(3x+2)=(3x+2)^2 +1