Answer:
An experimental research and particularly a quasi experimental study.
Step-by-step explanation:
An <em>experimental research</em> is one where the investigator study the effects from random samples he got and tested. the investigator manipulates parameters to considers some underlying factors in order to arrive at a conclusion. it is usually used to investigate relationships between variable and make comparison. In this case the investigator is conducting a research on how the consumption of oatmeal in adults reduces the level of bad cholesterol, he measures and study the level of bad cholesterol for 6months and then compare their results.
for example, I can conduct an extensive experimental study on the long term effects of exhaust fumes on the passengers (particularly adults between the ages of 25-50) of public transport in Nigeria. this will be studied and their effects will be compared and a conclusion will be reached on the exposure and the non exposure as the case maybe. most underlying conditions of experimental study are under the direct control of the researcher of the investigator. there are three different types of experimental research ; Pre-experimental study, quasi-experimental study and true-experimental study.
Answer: 1/3
Step-by-step explanation:
Number of red marbles = 5
Number of blue marbles = 9
Number of yellow marbles = 8
Number of and black marbles = 6
Total number of marbles = 28
If Taylor pulled out a yellow one and didn't replce it, there'll be 27 marbles left since one has been removed, then the probability of picking blue marbles will be:
= Number of blue marbles / Total marbles
= 9 / 27
= 1/3
The probability of picking a blue marble is 1/3.
Answer:
5 < x
Step-by-step explanation:
28<6x-2
Add 2 to each side
28+2<6x-2+2
30 < 6x
Divide each side by 6
30/6 < 6x/6
5 < x
Answer:
Your <u>correct</u> answer is 14t - 40
Step-by-step explanation:
Combine like terms:
10t + 3t + t = 14t
Since there are no other integers, just tag on the -40:
14t - 40
**please mark brainliest!!
Problem: find 0 ≤ x ≤ 28 such that x^85 ≡ 6 modulo 35.
By Fermat-Euler theorem:
If a and n are coprime, i.e. (a,n)=1, then
a^phi(n) ≡ 1 mod n
where phi(n)=totient function, the number of positive integers less than n that is coprime with n.
for n=35, phi(35)=24 calculated as follows:
There are 10 positive integers from 1 to 34 which are NOT coprime with 35, namely {5,7,10,14,15,20,21,25,28,30}.Therefore phi(35)=34-10=24
From Fermat-Euler theorem,
x^(phi(35) = x^24 ≡ 1 modulo 35 since (24,35)=1, i.e. 24 and 35 are coprime.
=>
x^12 ≡ ± 1 modulo 35. ...........(1)
and
x^85 ≡ x^(85-3*24) ≡ x^(85-72) ≡ x^(13) ≡ 6 mod 35 ............(2)
Substituting (1) in (2)
x^(12)*x ≡ 6 mod 35
=>
(+1)*x = 6 mod 35 or (-1)*x ≡ 6 mod 35
x ≡ 6 mod 35 x ≡ -6 mod 35 (rejected)
=> x=6
So
6^85 ≡ 6 mod 35
If any clarifications are needed or if you find any errors, please post.
