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FrozenT [24]
3 years ago
15

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Tomtit [17]3 years ago
8 0
Well all you have to do is add 3.2 and 4.58 together giving you the answer of 7.78. keep in mind Omar's height isn't relevant to the question.
ipn [44]3 years ago
4 0
Easy. their total weight is/was 7.78 kilograms. they threw the 54.5 cm to htrow you off
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Drawing Conclusions
maksim [4K]

Answer:

Some of the Exponents = -2 that is true, not 2.

Step-by-step explanation:

Let's check one at a time.

(a)The 6 without an exponent is equivalent to the 6 having a 0 exponent.

6^{0} =1 and 6^{1} = 6 (no exponent. 6 \neq 1 therefore this statement is False.

(b)The sum of the exponents is -2.

let's check , if the base is same we can add the exponents that is the exponent rule.(well established).

if we add exponents in the given expression we get.

6^{1} 6^{0} 6^{3} =6^{1+0+(-3)} =6^{-2}, therefore we can see that the sum of the exponents = -2 this is true.

(c) An equivalent expression is 65.6-7, lets evaluate our above expression, it is equal to \frac{1}{36} which we can see that \frac{1}{36}  \neq 65.6-7 ,therefore this statement is false as well.

3 0
3 years ago
How to find the inverse of g(x) = -3 +(3/5)x​
nasty-shy [4]

Answer:

g^-1(x)=5x/3 +5

3 0
3 years ago
a bottle contains 4 fluid ounces of medicine. About how many milliliters of medicine are in the bottle?
yarga [219]
There is 118.2941184 milliliters in four fluid ounces
4 0
3 years ago
Sixty-four is the product of eight and the sum of a number and six.
-BARSIC- [3]

Answer:

64 is the sum of the numbers

58 + 6 = 64

PLEASE MARK ME AS BRAINLIEST

5 0
2 years ago
A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess
maxonik [38]

Answer:

Total weight of the wheat placed on 45th square will be = 1.26\times 10^{6}tons

Step-by-step explanation:

King rewarded the inventor of chess by giving grain of wheat on every square of the chess board. He places one  grain of wheat on first square, 2 on second, 4 on 3rd, 8 on 4th and so on.

In fact he places grains of wheat in a progression S = 1, 2, 4, 8, 16.........n terms where value of n is 64.

We can rewrite the progression as S = 2°, 2, 2², 2³,.........n terms (n = 64)

In a geometric progression we know the nth term = a(r^{n-1})

where a = first term of the series, r = common ratio, n = number of terms

Now we have to calculate the weight of all wheat placed on 45th square.

So we will put the values in the given formula 45th term =

1\times (2^{45-1}) = 2^{44}=1.76\times 10^{13}

Then the weight of wheat will be = 2.51\times 10^{9}pounds=1.26\times 10^{6}tons



7 0
3 years ago
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