1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
enyata [817]
3 years ago
15

A college parking lot is 140 ft long and 90 ft wide. The college wants to increase the area of the lot by 29% by adding strips o

f equal width to one end and one side. (So, the new shape will be a larger rectangle.) Find the width of one such strip. Round your answer to the nearest integer.
Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0
The initial dimenssions of the park lot are:

length: 140 ft
width: 90 ft

initial area: 140 * 90 = 12,600 ft^2

Area increased 29% = 12,600 * 1.29 = 16,254 ft^2

width of the strips: x

New length: 140 + x

New width: 90 + x

New area: (140+x)(90+x) = 16,254

Solution of the equation:

12600 + 230x + x^2 = 16254

=> x^2 + 230x - 3654 = 0

Use the quadratic formula.

x = {-230 +/- √[ 230^2 - 4*1*(-3654) ]} / 2 =

x = 14.92

The other solution is negative so it is discarded.

Answer: 15 ft


 
You might be interested in
Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE
inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to 20\ units

Part 3) The area is equal to 25\ units^{2}

Step-by-step explanation:

we have

A(5,0), B(2,4), C(-2,1),D(1,-3)

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

A(5,0),B(2,4)

substitute in the formula

d=\sqrt{(4-0)^{2}+(2-5)^{2}}

d=\sqrt{(4)^{2}+(-3)^{2}}

d=\sqrt{25}

AB=5\ units

Find the distance BC

B(2,4), C(-2,1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}

BC=5\ units

Find the distance CD

C(-2,1),D(1,-3)

substitute in the formula

d=\sqrt{(-3-1)^{2}+(1+2)^{2}}

d=\sqrt{(-4)^{2}+(3)^{2}}

d=\sqrt{25}

CD=5\ units

Find the distance AD

A(5,0),D(1,-3)

substitute in the formula

d=\sqrt{(-3-0)^{2}+(1-5)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}        

AD=5\ units

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

B(2,4),D(1,-3)

substitute in the formula

d=\sqrt{(-3-4)^{2}+(1-2)^{2}}

d=\sqrt{(-7)^{2}+(-1)^{2}}

BD=\sqrt{50}\ units        

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

BD^{2}=AD^{2}+AB^{2}

substitute

(\sqrt{50})^{2}=5^{2}+5^{2}

50=50 -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

A=b^{2}

we have

b=5\ units

A=5^{2}=25\ units^{2}

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

P=4b

we have

b=5\ units

P=4(5)=20\ units

6 0
3 years ago
Write an equation of the line in slope-intercept from (answer fast pls ) <br><br> Y=
dimulka [17.4K]
The equation is y=1/3x+2
6 0
2 years ago
The area of the Pacific Ocean is 63,780,000 square miles. The Atlantic Ocean is 2.27 cross times 10 to the power of 7 square mil
olganol [36]

Answer:

4.11 * 10⁷ square miles

Step-by-step explanation:

Let P = pacific ocean

A = Atlantic ocean

P = 63,780,000 = 6.38 * 10⁷

Since A is 2.27 * 10⁷ square miles smaller than the pacific ocean,

The area of A = 6.38 * 10⁷ - 2.27 * 10⁷

The area of the atlantic ocean = 4.11 * 10⁷ square miles

4 0
3 years ago
Read 2 more answers
Select the correct answer from each drop-down menu. if f(x)=x^2+2x-3 and g(x)=x^2-9, find (f/g)(4) and (f+g)(4).
Nataly_w [17]

Answer:

(f/g)(4) = 3

(f + g)(4) = 28

Step-by-step explanation:

(f/g) = \frac{x^2+2x-3}{x^2-9}

(f + g) = 2x^2 + 2x -12

Simply plug in 4 for x in both equations to find you answer!

3 0
3 years ago
. ∆ABC ~ ∆DEF. Since the triangles are similar, the ratio of AB/DE must be the same as the ratio of ?/DF. What segment complete
givi [52]

Answer:

AC

Step-by-step explanation:

∆ABC ~ ∆DEF

AB/DE

∆ABC ~ ∆DEF

AC/DF

Answer: AC

5 0
3 years ago
Other questions:
  • Express the ratio 21:6 in its simplest form
    11·2 answers
  • How many codons could be formed if each codon was two bases long?
    5·1 answer
  • The ratio of the corresponding side lengths is 10:7 What is the ratio of the areas?
    13·1 answer
  • 2x² + y=6<br><br>please help​
    5·1 answer
  • Find the value of x and y in the given parallelogram
    12·1 answer
  • What else would need to be congruent to show that ABC DEF by SAS?A.C FB. C. D.A D
    9·1 answer
  • Yooooo please help lol
    15·2 answers
  • Consider these four statements about a line that passes through two points on a plane.
    8·1 answer
  • I'm having a bit of trouble finding out how to find the Domain of this function. Help please!
    6·1 answer
  • The standard form of 6050000 is given by​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!