Answer:
Step-by-step explanation:
given are the two following linear equations:
f(x) = y = 1 + .5x
f(x) = y = 11 - 2x
Graph the first equation by finding two data points. By setting first x and then y equal to zero it is possible to find the y intercept on the vertical axis and the x intercept on the horizontal axis.
If x = 0, then f(0) = 1 + .5(0) = 1
If y = 0, then f(x) = 0 = 1 + .5x
-.5x = 1
x = -2
The resulting data points are (0,1) and (-2,0)
Graph the second equation by finding two data points. By setting first x and then y equal to zero it is possible to find the y intercept on the vertical axis and the x intercept on the horizontal axis.
If x = 0, then f(0) = 11 - 2(0) = 11
If y = 0, then f(x) = 0 = 11 - 2x
2x = 11
x = 5.5
The resulting data points are (0,11) and (5.5,0)
At the point of intersection of the two equations x and y have the same values. From the graph these values can be read as x = 4 and y = 3.
20,000 x 25 = 500,000
500,000 divided by 100 = 5,000 members are lost.
Members left = 15,000
Members added = 10,000
Members every year = Members left + Members added
= 15,000 + 10,000
= 25,000
We need to get the limits first. When y = 0
0 = 64x - 8x^2
x = 0 and x = 8
The volume is
V = ∫ y dx from 0 to 8
V = ∫ (64x - 8x^2) dx from 0 to 8
V = 32x^2 - 8x^3/3 from 0 to 8
V = 682.67<span />
Answer:
B) 0.283
Step-by-step explanation:
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
25% of the students drive themselves to school.
This means that 
Class of 18 students
This means that 
What would be the probability that at least 6 students drive themselves to school?
This is

In which

So









Closest option is B, just a small rounding difference.
Hi, shown is one possible net.