Answer:
A. 1
B. 
.
Step-by-step explanation:
We have been given an equation of a line 
.
A. We know that slope of parallel lines is always equal,
We can see that slope of our given line is 1, therefore the slope of the line parallel to our given line would be 1.
B. We know that the product of slopes of two perpendicular lines is .
Let m represent slope of perpendicular to our given line, then:
Therefore the slope of the line perpendicular to our given line would be .
Answer:
About <em>4 hours.</em>
Step-by-step explanation:
To find the answer we will <em>add both percentages</em> of <u><em>Watching TV</em></u> and <u><em>Homework</em></u>. 8% + 13% = <em>21%</em>. Now we will <em>divide 100 by 21</em> and we get<em> 4 hours a day.</em>
-0.16666666666 which equals -1/16.
35 3/4= 35.75 and 1/8=0.125
35.75/0.125= 286
Answer: a) Yes, there is enough fance
b) 58.1° and 47.9°
c) The city will not approve, because 1/3 of the area is just 2220.5ft²
Step-by-step explanation:
a) using law of cosines: x is the side we do not know.
x² = 126² + 110² - 2.126.110.cos74°
x² = 20335.3
x = 142.6 ft
So 150 > 142.6, there is enough fance
b) using law of sine:
sin 74/ 142.6 = sinα/126 = sinβ/110
sin 74/ 142.6 = sinα/126
0.006741 = sinα/126
sinα = 0.849
α = sin⁻¹(0.849)
α = 58.1°
sin 74/ 142.6 = sinβ/110
sin 74/ 142.6 = sinβ/110
0.006741 = sinβ/110
sinβ = 0.741
β = sin⁻¹(0.741)
β = 47.9°
Checking: 74+58.1+47.9 = 180° ok
c) Using Heron A² = p(p-a)(p-b)(p-c)
p = a+b+c/2
p=126+110+142.6/2
p=189.3
A² = 189.3(189.3-126)(189.3-110)(189.3-142.6)
A = 6661.5 ft²
1/3 A = 2220.5
So 2300 > 2220.5. The area you want to build is bigger than the area available.
The city will not approve
