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3 years ago

What is the answer to 8(-8x-8)=18

Mathematics

2 answers:

Zigmanuir [339]3 years ago

5 0

Answer:

x= -1 9/32

Step-by-step explanation:

tekilochka [14]3 years ago

4 0

Answer:

x = - $\frac{41}{32}$

Step-by-step explanation:

8(-8 x - 8) =18

(-64) x - 64 = 18

(-64)x = 18 +64

(-64) x = 82

Therefore x = 82÷ (-64)

x = - $\frac{41}{32}$

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levacccp [35]

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Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

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Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

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AB and BC form a right angle at point B. If A = (-3,-1) and B = (4,4), what is the equation of BC

m_a_m_a [10]

Answer:

$y=-1.4x+9.6$

Step-by-step explanation:

If A = (-3,-1) and B = (4,4), the slope of AB is

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$y-4=-1.4(x-4)\\ \\y-4=-1.4x+5.6\\ \\y=-1.4x+9.6$

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Answer:

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Step-by-step explanation:

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