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3 years ago

SOMONE PLEASEE HELPPP MEEEEEEEE!!!

Mathematics

1 answer:

katen-ka-za [31]3 years ago

5 0

Answer:

? = 36 degrees

Step-by-step explanation:

To find this measure, we use the appropriate trigonometric ratio

from the question, the angle faces the length 26 which represents the opposite

the length 44 faces the angle 90, which is the hypotenuse

The trigonometric ratio that connects both is the sine

The sine of an angle is the ratio of the opposite to the hypotenuse

Thus;

sine ? = 26/44

? = arc sine (26/44)

? = 36

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What is the area of a shape with points a 5 -8 b 11, -8 c 11,0 d 6,-3 e 4,-3

Dmitriy789 [7]

Answer:

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

= 11 × 8

= 88 square units

Area of trapezoid OGEF = $\frac{1}{2}(b_1+b_2)\times h$

= $\frac{1}{2}(\text{GE+OF)}\times (\text{OG})$

= $\frac{1}{2}(3+6)\times 4$

= 18 units²

Area of trapezoid GCDE = $\frac{1}{2}(\text{GC+DE)}\times (\text{GE})$

= $\frac{1}{2}(7+2)\times 3$

= 13.5 units²

Area of triangle AFH = $\frac{1}{2}(\text{Base})\times (\text{Height})$

= $\frac{1}{2}(5)(2)$

= 5 units²

Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)

= 88 - (18 + 13.5 + 5)

= 88 - 36.5

= 51.5 units²

Therefore, area of the given polygon is 51.5 units²

3 0

4 years ago

My Notes A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1600 hours and

Evgen [1.6K]

Answer:

The bulbs should be replaced each 1436.9 hours.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1600, \sigma = 70$