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cricket20 [7]
3 years ago
15

Leticia tretched for 8 minutes then jogged around her block several times .it takes her 6 minutes to run around the block once .

she spent 38 minutes exercising how many tims did leticia jog aound the block ?
Choose two answers: one for the equation that models this situation and one for the correct answer

A. Equation: 8 + 6x = 38
B. Answer: 4 times around the block
C. Equation: 6 + 8x = 38
D. Answer: 5 times around the block
Mathematics
1 answer:
Luda [366]3 years ago
7 0

Answer:

Your answer would be A and D hope this helps :)


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Round this number 43.0129 hundredths place
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Answer:

43.013

Step-by-step explanation:

Theres a nine in the thousands place it has to be 5 or higher to round so its high enough.

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A class has `\$140` for tickets to a science museum.
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Alma is correct
I hope this helps you!
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A water tank has a diameter of 15 ft and is 22 ft high. a. What is the volume of the tank in ft?? b. In m?? c. In cm?
rodikova [14]

Answer:

a) V = 3887.72 ft^{3}

b)V = 104.97 m^{3}

c)V = 104,968,468.538 cm^{3}

Step-by-step explanation:

A tank has the format of a cylinder.

The volume of the cylinder is given by:

V = \pi r^{2}h

In which r is the radius and h is the heigth.

The problem states that the diameter is measured to be 15.00 ft. The radius is half the diameter. So, for this tank

r = \frac{15}{2} = 7.50 ft

The height of the tank is 22 ft, so h = 22.

a) Volume of the tank in ft^{3}:

V = \pi r^{2}h

V = pi*(7.5)^2*22

V = 3887.72 ft^{3}

b) Volume of the tank in m^{3}:

We must convert both the radius and the height to m.

Each feet has 0.30 m, so:

Radius:

1 feet - 0.30m

7.5 feet - r m

r = 7.5*0.30

r = 2.25m

Height

1 feet - 0.30m

22f - h m

h = 22*0.30

r = 6.60m

The volume is:

V = \pi r^{2}h

V = pi*(2.25)^2*6.60

V = 104.97 m^{3}

c) Volume of the tank in cm^{3}:

Each m has 100 cm.

So r = 2.25m = 225cm

h = 6.60m = 660cm

The volume is:

V = \pi r^{2}h

V = pi*(225)^2*660

V = 104,968,468.538 cm^{3}

7 0
4 years ago
What is 1999876•647789
Thepotemich [5.8K]
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3 years ago
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From her house, Meg must drive 8 miles due north to visit her aunt. From her house, she must drive 15 miles due east to visit he
yanalaym [24]

Answer:

The straight line distance is 17 miles from Meg's aunt's house to her grandmother's house.

Step-by-step explanation:

We have drawn the diagram for your reference.

Given:

Meg have to drive 8 miles due north to visit her aunt.

From diagram we can say;

BA = 8 miles

Also she has to drive 15 miles due east to visit her grandmother.

From diagram we can say;

BC = 15 miles

We need to find the straight-line distance from Meg's aunt's house to her grandmother's house i.e we need to find AC from diagram.

Now We can Assume it as a right angled triangle.

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Now taking Square root on both side we get;

\sqrt{AC^2}= \sqrt{289} \\ \\AC =17 \ miles

Hence The straight line distance is 17 miles from Meg's aunt's house to her grandmother's house.

8 0
4 years ago
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