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Alex
3 years ago
13

Find the first 4 terms for the given function. ƒ (n) = n^3 - 1

Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0

Answer:

0,7,26, and 63

Step-by-step explanation:

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Ethan correctly 80% of the total questions on his history Test. He correctly answers 32 question how many questions are on Ethan
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40 questions because 80% of 40 is 32
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4 years ago
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A scale on a map is 1:5000000 Two towns are 7cm apart on the map. What is the actual distance between the towns
Andrej [43]

Answer:350km

Step-by-step explanation:

6 0
3 years ago
For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f
butalik [34]

\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k

Let

\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k

The curl is

\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)

where \partial_\xi denotes the partial derivative operator with respect to \xi. Recall that

\vec\imath\times\vec\jmath=\vec k

\vec\jmath\times\vec k=\vec i

\vec k\times\vec\imath=\vec\jmath

and that for any two vectors \vec a and \vec b, \vec a\times\vec b=-\vec b\times\vec a, and \vec a\times\vec a=\vec0.

The cross product reduces to

\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

\nabla\times\vec f=\vec0

which means \vec f is indeed conservative and we can find f.

Integrate both sides of

\dfrac{\partial f}{\partial y}=2xze^{2xyz}

with respect to y and

\implies f(x,y,z)=e^{2xyz}+g(x,z)

Differentiate both sides with respect to x and

\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}

2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}

4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}

\implies g(x,z)=4\sin(xz^2)+h(z)

Now

f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)

and differentiating with respect to z gives

\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}

2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}

\dfrac{\mathrm dh}{\mathrm dz}=0

\implies h(z)=C

for some constant C. So

f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C

3 0
4 years ago
10 is 8% of a, and 5 is 4% of b. c equals b/a. What is the value of c?? step by step explanation pls...
klio [65]

Answer:

c = 1

Step-by-step explanation:

"10 is 8% of a":     0.08a = 10, or <u>a = (10/0.08)</u>

"5 is 4% of b":      0.04b =  5, or <u>b = (5/0.04)</u>

"c equals b/a":       c = (b/a)

----

What is the value of c?

c = (b/a)

c = ((5/0.04)/(10/0.08))

c = (5/0.04)*(0.08/10)

c = (5/10)*(0.08/0.04)

c = (1/2)*(2)

<u>c = 1</u>

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2 years ago
Can anyone guess what game i was playing by the looks of it
OLEGan [10]

Answer:

A VR car game and an iphone

Step-by-step explanation:

:)

7 0
3 years ago
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