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3 years ago

How many triangular faces does a rectangular pyramid have?

Mathematics

1 answer:

Advocard [28]3 years ago

5 0

A rectangular pyramid has a rectangular base and 4 triangular faces.

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A small radio transmitter broadcasts in a 50 mile radius. If you drive along a straight line from a city 65 miles north of the t

mart [117]

Answer:

29% of the drive

Step-by-step explanation:

The plot of the problem is:

Transmitter at origin (0,0)

City to the north at (0,70)

City to the east at (74,0)

The path from city to city is a line with slope:

m = (-70)/74 = -35/37

and y-intercept at y = 70, so the equation is y = (-35/37)*x + 70.

The transmitter reach the area enclosed by the next circle:

x^2 + y^2 = 53^2

See the picture attached

The intersection is gotten from the picture or solving:

x^2 + [(-35/37)*x + 70]^2 = 53^2

the points approximately are: (24.1, 47.2) and (45.8, 26.7)

From Pythagorean theorem the total distance of the trip is:

d1 = √(70^2 + 74^2) ≈ 101.9 miles

And the distance when the signal is picked up is:

d2 =√ [(45.8 - 24.1)^2 + (47.2 - 26.7)^2] ≈ 29.9 miles

You will pick up a signal from the transmitter in (d2/d1)*100 = 29% of the drive.

7 0

2 years ago

Please helppp me :( it’s c^4/c^3

ira [324]

Answer:

Step-by-step explanation:

Because $\frac{c}{c}$ is 1 the equation turns into...

$c^{4-3}$

which equals...

$c^{1}$

and $c^{1}$ is just c

7 0

2 years ago

An airplane flies 750 miles due west in 1 1! 2hours and 750 miles due south in 2 hours. what is the average speed of the airplan

LiRa [457]

Use the Pyth. Theorem to calculate the total distance flown by the plane in 3 1/2 hours:

d = sqrt(750^2 + 750^2) = 750sqrt(2) miles

Now divide this distance by the total time (3 1/2 hours):

750sqrt(2) miles
---------------------- = 303 miles per hour average
3.5 hours

3 0

3 years ago

The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at

Fynjy0 [20]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.

The mean $\bar X$ = 7.3 days.

The standard deviation = 6.2 days.

df = n-1

$= 30-1 \\ =29$

The importance level is $\alpha$ = 0.10

The table value is calculated with a function excel 2010:

$= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ = t_{al(2x-1)}= 1.699127$

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

$\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1} \frac{S}{\sqrt{n}}$

$=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29} \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127 (1.13196) \\\\=5.37 \leq \mu \leq 9.22 \\$

It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.

7 0

3 years ago

Please help my brain is dead -_-

ASHA 777 [7]

With out deductions the total will be 729.16. but with the deductions the income will be 500.

5 0

3 years ago

Read 2 more answers