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sergij07 [2.7K]
3 years ago
13

Can 29/48 be simplified

Mathematics
2 answers:
elixir [45]3 years ago
5 0
29/48 Can not be simplefied... Nothing will go into 48 that can also go into 29.
So 29/48 Is your final answer.
NeX [460]3 years ago
5 0
Well actually we can't simplified or reduce more the final answer is 29/48 :) 
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Do u just plot the numbers on the graph like (1,26)???
kvv77 [185]

Answer:

Yes

Step-by-step explanation:

Make sure you plot each number on the right axis. :)

4 0
3 years ago
What is the y-coordinate of the solution for the system of equations?
enot [183]
Y= 12 - x

27 + 3( 12 - x ) = 2x
7 0
3 years ago
Read 2 more answers
My brother is in 6th grade and needs help with his math. I tried to help but I can't find any answers on it.
In-s [12.5K]

Answer:

Question 1) 17.4

Question 2) 1.7

Question 3) 2.8

Question 4) 8.6

Step-by-step explanation:

Mean absolute deviation is the average distance between the data points from the set to the mean point of the data set. It shows the variability in data or how much the data points are spread.

method to calculate Mean absolute deviation:

a. calculate mean

b. calculate absolute deviation of each data point

c. add all the deviations

d. divide absolute deviation by number of points

mean absolute deviation = ∑lx_{i}-xl / n

The given problem has four sub-parts

Solution 1:

Mean= (78+99+90+80+55+56+102+88+60+42)/10

            =  750/10

            =  75

Mean absolute deviation= ( I 78-75 I + I 99-75 I+I 90-75 I + I 80-75 I +

                                             I 55-75 I + I 56-75 I + I 102-75 I + I 88- 75 I +

                                             I 60-75 I + I 42-75 I) /10

         =  (174)/10

        =  17.4

Solution 2:

Mean = (10+13+7+12+9+8+12+10+11+13)/10

              =  (105)/10

              = 10.5

Mean absolute deviation = ( I 10-10.5 I + I 13-10.5 I + I 7-10.5 I + I 12-10.5 I +

                                              I 9-10.5 I + I 8-10.5 I + I 12-10.5 I + I 10-10.5 I +

                                               I 11-10.5 I + I 3-10.5 I) /10

       =   17/10

       = 1.7

Solution 3:

Mean= (1+7+10+5+3+3+6+12+9+4)/10

            =  60/10

            =  6

Mean absolute deviation  = ( I 1-6 I + I 7-6 I + I 10-6 I + I 5-6 I + I 3-6 I +

                                               I 3-6 I + I 6-6 I + I 12- 6 I + I 9-6 I + I 4-6 I) /10

         = (28)/10

        =  2.8

Solution 4:

Mean= (30+46+25+45+18+25+15+32+40+24)/10

            =  300/10

            =  30

Mean absolute deviation  = ( I 30-30 I + I 46-30 I + I 25-30 I + I 45-30 I +

                                               I 18-30 I + I 25-30 I + I 15-30 I + I 32-30 I +

                                               I 40-30 I + I 24-30 I) /10

         = (86)/10

        =  8.6

!

8 0
3 years ago
Determine if the following system of equations has no solutions 4x+3y= -8 -8x-6y= 16
cupoosta [38]

\begin{cases} 4x+3y=-8\\\\ -8x-6y=16 \end{cases}~\hspace{10em} \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

4x+3y=-8\implies 3y=-4x-8\implies y=\cfrac{-4x-8}{3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{4}{3}} x-\cfrac{8}{3} \\\\[-0.35em] ~\dotfill\\\\ -8x-6y=16\implies -6y=8x+16\implies y=\cfrac{8x+16}{-6} \\\\\\ y=\cfrac{8}{-6}x+\cfrac{16}{-6}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{4}{3}} x-\cfrac{8}{3}

one simple way to tell if both equations do ever meet or have a solution is by checking their slope, notice in this case the slopes are the same for both, meaning the lines are parallel lines, however, notice both equations are really the same, namely the 2nd equation is really the 1st one in disguise.

since both equations are equal, their graph will be of one line pancaked on top of the other, and the solutions is where they meet, hell, they meet everywhere since one is on top of the other, so infinitely many solutions.

3 0
2 years ago
11. Which matrix represents the system of equations below?
dimulka [17.4K]

Answer:

\left[\begin{array}{cccc}-12&-13&13&|15\\7&-10&-3&|11\\7&14&5&\:\:\:|-5\end{array}\right]

Step-by-step explanation:

The system of equations is;

-12x-13y +13z =15

7x-10y-3z = 11

7x+14y +5z = -5

The coefficient matrix is \left[\begin{array}{ccc}-12&-13&13\\7&-10&-3\\7&14&5\end{array}\right]

The constant matrix is \left[\begin{array}{c}15\\11\\-5\end{array}\right]

The augmented matrix is \left[\begin{array}{cccc}-12&-13&13&|15\\7&-10&-3&|11\\7&14&5&\:\:\:|-5\end{array}\right]

4 0
3 years ago
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