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Colt1911 [192]
3 years ago
10

What is p^m ⋅ p^n equal to? p^m − n p^m + n p^m ⋅ n p^m ÷ n. please show work

Mathematics
1 answer:
Inessa05 [86]3 years ago
8 0
<h3>Answer:</h3>

p^(m+n) . . . . . . . parentheses are required

<h3>Explanation:</h3>

The answer follows directly from the rules of exponents:

... (a^b)×(a^c) = a^(b+c)

Here, you have a=p, b=m, c=n, so

... (p^m)×(p^n) = p^(m+n)

_____

<em>Where the rule comes from</em>

An exponent sigifies <em>repeated multiplication</em>. That is ...

... p^3 = p·p·p . . . . . . . the exponent means p is a factor 3 times

... p^2 = p·p . . . . . . . . .the exponent means p is a factor 2 times

When we multiply these terms together, we have ...

... (p^3)×(p^2) = (p·p·p)×(p·p) = p·p·p·p·p = p^(2+3) = p^5

The number of times p is a factor of the product is the total of the number of times p is a factor in the factors of the product.

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3 years ago
I’m so confused help please
lozanna [386]

Answer:

  B.  0

Step-by-step explanation:

If you subtract the right side expression and simplify, you get ...

  4/5(20x +5) -(16x -2) = 0

  16x +4 -16x +2 = 0

  6 = 0 . . . . . . . . . . . . false

There is no value of x that will make this true. There are no solutions.

5 0
2 years ago
Jimmy’s new cell phone cost him $49.99 when he signed a 2 year plan, which was 75% off the original place. What was the original
Sati [7]
If Jimmy's new cell cost him $49.99 with a 75% discount, then $49.99 is <span>100%−75%=25%</span><span> of the original price.
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6 0
3 years ago
Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin
icang [17]

Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

\frac{xy'}{(x^2+7)y}=cosx+\frac{e^{3x}}{y}

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}

y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}

y'-\frac{cosx(x^2+7)}{x}y=\frac{e^{3x}(x^2+7)}{x}

It is linear differential equation because  this equation is of the form

y'+P(x)y=g(x)

Compare it with first order first degree linear differential equation

y'+P(x)y=g(x)

P(x)=-\frac{cosx (x^2+7)}{x},g(x)=\frac{e^{3x}(x^2+7)}{x}

\frac{dy}{dx}=\frac{(x^2+7)(ycosx+e^{3x})}{x}

Homogeneous equation

\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}

Degree of f and g are same.

f(x,y)=(x^2+7)(ycosx+e^{3x}),g(x,y)=x

Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

3 0
3 years ago
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