I’m pretty sure it’s
6x-10y+x^2-21
Unless I read it wrong then sorry

$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
For this case we must find the value of n of the following equation:

Taking common factor "n" from the left side of the equation we have:

Multiplying by 5 on both sides of the equation:

Dividing between 6 on both sides of the equation:

Thus, the value of n is 20.
Answer:
